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9966 [12]
3 years ago
15

1. |4n-15|=|n| 2. |2c+8|=|10c| can you please show the work for both

Mathematics
1 answer:
Alja [10]3 years ago
8 0

Problem 1

<h3>Answers: n = 3 or n = 5</h3>

---------------

Work Shown:

|4n - 15| = |n|\\\\4n - 15 = n \ \text{ or } \ 4n-15 = -n\\\\-15 = n-4n \ \text{ or } \ -15 = -n-4n\\\\-15 = -3n \ \text{ or } \ -15 = -5n\\\\-3n = -15 \ \text{ or } \ -5n = -15\\\\n = \frac{-15}{-3} \ \text{ or } \ n = \frac{-15}{-5}\\\\n = 5 \ \text{ or } \ n = 3\\\\

==============================================

Problem 2

<h3>Answers: c = 1 or c = -2/3</h3>

-----------------------

Work Shown:

|2c+8| = |10c|\\\\2c+8 = 10c \ \text{ or } \ 2c+8 = -10c\\\\8 = 10c-2c \ \text{ or } \ 8 = -10c-2c\\\\8 = 8c \ \text{ or } \ 8 = -12c\\\\8c = 8 \ \text{ or } \ -12c = 8\\\\c = \frac{8}{8} \ \text{ or } \ c = \frac{8}{-12}\\\\c = 1 \ \text{ or } \ c = -\frac{2}{3}

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Write the equation of a line in slope-intercept form that passes through the given points.
ruslelena [56]

Answer:

<h2>         y = 0.25x + 2</h2>

Step-by-step explanation:

\bold{slope\, (m)=\dfrac{change\ in\ Y}{change\ in\ X}=\dfrac{y_2-y_1}{x_2-x_1}}

(0, 2)    ⇒     x₁ = 0,  y₁ = 2

(-4, 1)     ⇒     x₂ = -4,  y₂ = 1

So the slope:

\bold{m=\dfrac{1-2}{-4-0}=\dfrac{-1}{-4}=0.25}

The point-slope form of the equation of the line passing through point (x₀,y₀) and with slope m is:  y - y₀ = m(x - x₀)

m = 0.25

(0, 2)    ⇒     x₀ = 0,  y₀ = 2

Therefore:

               y - 2 = 0.25(x - 0)

               y - 2 = 0.25x                  {add 2 to both sides}

               y = 0.5x + 2          ←  the slope-intercept form of the equation

5 0
3 years ago
1/20
Vladimir [108]

Answer:

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Step-by-step explanation:

120 is the common number by 40 and 30. trust me on this I'm really good at this subject in math.

8 0
3 years ago
Choose the equation below that represents the line passing through the point -3,-1 with the slope of four
tresset_1 [31]

Answer:

y+1 = 4(x+3)

Step-by-step explanation:

To write the equation of a line use the point slope form by substituting m = 4 and the point (-3,-1).

y - y_1 =m(x-x_1)\\y --1 = 4(x--3)\\y+1 = 4(x+3)

5 0
3 years ago
I need help on number 31
koban [17]

Answer:

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Step-by-step explanation:


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3 years ago
Can someone help me out with number 2?
Norma-Jean [14]
\sin255^o=\sin(300^o-45^o)=\sin300^o\cos45^o-\cos300^o\sin45^o= \\\\=- \frac{ \sqrt{3} }{2}\cdot  \frac{ \sqrt{2} }{2}- \frac{1}{2} \cdot  \frac{ \sqrt{2} }{2}=-      \frac{ \sqrt{6} }{4} -  \frac{ \sqrt{2} }{4}=  -\frac{  \sqrt{6}+\sqrt{2} }{4}

5 0
4 years ago
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