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igomit [66]
2 years ago
5

The following table shows how far a bus has gone in t hours. Which of the following equations represents this information?

Mathematics
1 answer:
drek231 [11]2 years ago
5 0

Step-by-step explanation:

You need to attach the table in order to get an answer.

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Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of
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Answer:

i(x)=12 \times (1+\frac{0.9}{12})^{12x} and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by i(x)=12 \times (1.9)^{x}, where x is the number of years.

Since, i(x)=12 \times (1.9)^{x}

i.e. i(x)=12 \times (1+0.9)^{x}.

Therefore, the monthly growth rate function becomes,

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{x \times 12}.

i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Hence, the monthly growth rate is i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Also, the growth factor is given by \frac{0.9}{12} = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

4 0
3 years ago
What is 4/6/10 plus 6/10 fractions
Paul [167]

Answer:

5 and 1/5

Step-by-step explanation:

it is written like this 4 and 6/10 + 6/10

so its 4 and (6+6) 12/10


12-10= 2 = 1 and 1/5

4 +1= 5

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3 years ago
Hank invested a total of $20,000, part at 7% and part at 10%. How much did he invest at each rate if the total interest earned i
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Answer:

The amount invested at 7% is $12,000 while the amount invested at 10% is $8,000

Step-by-step explanation:

The given parameters are;

The total amount Hank invested = $20,000

The interest earned in one year = $1640

Hank invested part of the $20,000 at 7% interest and part of the $20,000 at 10%

Let the part invested at 7% = X and the part invested at 10% = Y, we have;

7% of X + 10% of Y = $1640 which gives;

0.07×X + 0.1×Y = $1640.....................(1)

X + Y = $20,000.................................(2)

Multiply equation (1) by 10 and subtract equation (1) from equation (2) to get;

X + Y - 10×(0.07×X + 0.1×Y) = $20,000 - 10×$1640

X - 0.7·X - Y - Y = $20,000 - $16,400 = $3,600

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X = $3,600/0.3 = $12,000

X = $12,000

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Y = $8,000

Therefore, the amount invested at 7% = $12,000 and the amount invested at 10% = $8,000.

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