All categories

3 years ago

What number must you add to complete the square? x^2 + 8x = -3

1 answer:

5 0

x^2 + 8x = -3
x^2 + 8x + 16 = -3 + 16
using a^2 + 2 a b + b^2 = (a+b)^2

x^2 + 8x + 16 = 13

(x +4)^2 = 13

answer : 16 is the number you must add to complete the square

You might be interested in

Can I get some help please?

mamaluj [8]

Answer:

1) 68

/ \

4 17

2 2

68=2*2*17

2) 104

/ \

4 26

/\ /\

2 2 2 13

104=2*2*2*13

3) 78

2 39

3 13

78=2*3*13

4) 225

9 25

/\ /\

3 3 5 5

225=3*3*5*5

Second Part:

1) 45

3 15

3 5

45=3*3*5

2) 70

2 35

5 7

70=2*5*7

3) 54

9 6

/\ /\

3 3 2 3

54=3*3*2*3

4) 126

3 42

3 14

7 2

126=3*3*7*2

3 0

2 years ago

6. HOT AIR BALLOON А balloon rises 340 feet into the air. Then it descends 130 feet.

Nezavi [6.7K]

Now it is at 210 feet

7 0

2 years ago

Read 2 more answers

What is the solution to sqrt 17-x=x+3? Show your work.

snow_lady [41]

Answer:

$x=1$

Step-by-step explanation:

Remember:

$(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2$

Given the equation $\sqrt{17-x}=x+3$ , you need to solve for the variable "x" to find its value.

You need to square both sides of the equation:

$(\sqrt{17-x})^2=(x+3)^2$

$17-x=(x+3)^2$

Simplifying, you get:

$17-x=x^2+2(x)(3)+3^2\\\\17-x=x^2+6x+9\\\\x^2+6x+9+x-17=0\\\\x^2+7x-8=0$

Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:

$(x-1)(x+8)=0$

Then:

$x_1=1\\x_2=-8$

Let's check if the first solution is correct:

$\sqrt{17-(1)}=(1)+3$

$4=4$ (It checks)

Let's check if the second solution is correct:

$\sqrt{17-(-8)}=(-8)+3$

$5\neq-5$ (It does not checks)

Therefore, the solution is:

$x=1$

3 0

3 years ago

Jason tracked the days of the week for the last 50 times he was assigned homework.

vovangra [49]

Answer:

Hello, mizuki here to help!

The correct answer would be C

Step-by-step explanation:

Ok, so the total of homework he got was 50, and the number of homework he got in monday was 16.

So.... it should be expressed as 16/50 which would be 0.32

3 0

3 years ago

What is the range of a cosine function?

klemol [59]

The smallest y can be is y = -1. The largest it can be is y = 1. The value of y can be anything in between. The value of y is a real number.

Answer: Choice D) All real numbers between -1 and 1 including -1 and 1

Note: we can write that as $-1 \le y \le 1$ which in interval notation would look like $[-1, 1]$ . The square brackets tell us to include the endpoints.

4 0

2 years ago