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3 years ago

A track is 200 meters long. How many times must Julius run around the track to run 3 kilometers ?

1 answer:

4 0

Here is how you would do this: If there are 1000 meters in one kilometer, and you know that this track is 200 meters long, then you can find how many times Julius must run around the track in order to reach ONE kilometer:

1000 meters / 200 meters = 5 times in around the track for ONE kilometer.

To find how many times Julius would need to run around to reach THREE kilometers you simply do the following:

5 x 3 = 15 ---> Julius would need to run around the track 15 times in order to reach 3 kilometers.

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Which function has a greater rate of change? Function A: x 1.5 2.5 3.5 4.5 5.5 y 5 0 –5 –10 –15 Function B: y = –4.5x + 15 Funct

expeople1 [14]

Answer:

Function A has a rate of change of -5 and Function B has a rate of change of -4.5, so Function B has a greater rate of

Step-by-step explanation:

Function A:

$\begin{array}{cccccc}x & {1.5} & {2.5} & {3.5} & {4.5} & {5.5} \ \\ y & {5} & {0} & {-5} & {-10} & {-15} \ \end{array}$

Function B:

$y = -4.5x + 15$

Required

Which has a greater rate of change

The rate of change of function A is calculated as thus:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where:

$(x_1,y_1) = (1.5,5)$

$(x_2,y_2) = (2.5,0)$

So, we have:

$m = \frac{0-5}{2.5 - 1.5}$

$m = \frac{-5}{1}$

$m = -5$

For function B

The general function is:

$y = mx + b$

Where

m is the rate of change

By comparing $y = mx + b$ to $y = -4.5x + 15$

$m = -4.5$

So, we have that:

Function A has a rate of -5; function B has a rate of -4.5.

By comparison: -4.5 is greater than 5

Hence, function B has a greater rate.

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