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Advocard [28]
4 years ago
10

Evaluate 13-0.75w+8x13−0.75w+8x13, minus, 0, point, 75, w, plus, 8, x when w=12w=12w, equals, 12 and x=\dfrac12x=

Mathematics
1 answer:
hodyreva [135]4 years ago
4 0

Answer:

8

Step-by-step explanation:

we have the expression

13-0.75w+8x

For w=12, x=1/2

To evaluate, substitute the value of w and the value of x in the expression

13-0.75(12)+8(1/2)

13-9+4

4+4

8

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What are the variables in each graph
Svet_ta [14]

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Answer:

  1. time, volume
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Step-by-step explanation:

The axis labels answer this question. The horizontal axis is the independent variable; the vertical axis is the dependent variable.

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Find each measurement indicated. Round your answer as the nearest tenth. HELP PLEASE!!!!!! URGENT
MaRussiya [10]

Answer:

(1) length AB = 21.0

(2) length BC = 45.0

Step-by-step explanation:

(1) To determine AB, apply Cosine rule;

|AB|^2 = |AC|^2 + |BC|^2 \ - \ 2[|AC| \times |BC]cos \ C\\\\|AB|^2 = 13^2 + 29^2 \ - \ 2(13 \times 29) cos(41)\\\\|AB|^2 = 1010 - 569.05\\\\|AB|^2 = 440.95\\\\|AB|= \sqrt{ 440.95} \\\\|AB| = 21.0

(2) To determine BC, also apply cosine rule;

|BC|^2 = |AB|^2 + |AC|^2 \ - \ 2[|AB| \times |AC]cos \ A\\\\|BC|^2 = 30^2 + 21^2 \ - \ 2(30 \times 21) cos(123)\\\\|BC|^2 = 1341 - (-686.245)\\\\|BC|^2 = 1341 + 686.245\\\\ |BC| = 2027.245\\\\|BC|= \sqrt{ 2027.245} \\\\|BC| = 45.0

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3 years ago
Find the equation of a line in slope intercept form, passing through (2,5) and parallel to 2x+3y=-12
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2x+3y=-12\ \ \ \Rightarrow\ \ \ 3y=-2x-12\ \ \ \Rightarrow\ \ \ y=- \frac{2}{3} x-4\\\\y=mx+b\ \ ||\ \ y=- \frac{2}{3} x-4\ \ \ \Leftrightarrow\ \ \ m=-\frac{2}{3}\\\\the\ point\ slope\ form:\ y-y_1=m(x-x_1)\ \ \ and\ \ \ (x_1,y_1)=(2,5)\\\\y-5=-\frac{2}{3}(x-2) \ \ \Rightarrow\ \ \ y-5=-\frac{2}{3}x+\frac{4}{3}\ \ \ \Rightarrow\ \ \ y=-\frac{2}{3}x+5+1\frac{1}{3} \\\\the\ slope\ intercept\ form:\ \ \ y=-\frac{2}{3}x+6\frac{1}{3}\\\\ the\ slope:\ m=- \frac{2}{3},\ \ \ the\ intercept:\ b=6\frac{1}{3}
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