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Advocard [28]
3 years ago
10

Evaluate 13-0.75w+8x13−0.75w+8x13, minus, 0, point, 75, w, plus, 8, x when w=12w=12w, equals, 12 and x=\dfrac12x=

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0

Answer:

8

Step-by-step explanation:

we have the expression

13-0.75w+8x

For w=12, x=1/2

To evaluate, substitute the value of w and the value of x in the expression

13-0.75(12)+8(1/2)

13-9+4

4+4

8

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Janelle graphed a line through (−6, 5) that had a slope of −79. What is the y-coordinate of a point on the line that has an x-co
jeyben [28]

Answer:

The value of the y-coordinate is -706

Step-by-step explanation:

The equation of a straight line is;

y = mx + c

where m is slope and c is t-intercept

Given the slope, we can write the equation as;

y = -79x + c

we need to get c

Just put in the x and y values of the given point

X = -6 and y = 5

5 = -79(-6) + c

5 = 474 + c

c = 5-474 = -469

So the complete equation of the line would

be ;

y = -79x - 469

To get the y-coordinate of the point, just insert the x value into the equation;

y = -79(3) - 469

y = -237 - 469 = -706

4 0
2 years ago
After being exposed to an incredible shrinking machine, Halley's height decreased by 108 cm over 6 seco
uysha [10]

Answer:

it would be -18

Step-by-step explanation:

because you would divide 108 by 6 and you will get -18 each second

6 0
2 years ago
8.71 ×<img src="https://tex.z-dn.net/?f=10%5E%7B7%7D" id="TexFormula1" title="10^{7}" alt="10^{7}" align="absmiddle" class="late
Semmy [17]
It’s 87100000 Have Ah Good Day.
4 0
2 years ago
Read 2 more answers
A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

Fencing used ,P(x)=x+x+y+y+y=2x+3y

Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0
3 years ago
Holly missed 6 of 181 school days this year. Approximately what percent of school days was Holly in attendance?
Natasha2012 [34]
181-6=175\\\\\frac{175}{181}\cdot100\%=\\\\\frac{17500}{181}\%=\\\\96.7\%\approx97\%\\\\Answer\ C
4 0
3 years ago
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