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zhenek [66]
3 years ago
12

What to do when a negative number is subtracted from a positive number?

Mathematics
1 answer:
pentagon [3]3 years ago
5 0
When you see the subtraction<span> (</span>minus<span>) sign followed by a </span>negative<span> sign, turn the two signs into a plus sign. Thus, instead of </span>subtracting<span> a </span>negative<span>, you're adding a </span>positive<span>, so you have a simple addition problem.</span>
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What equation allows you to calculate the force acting on an object?
Dahasolnce [82]
Force = mass x acceleration 
7 0
3 years ago
Read 2 more answers
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
4 years ago
A cake has a circumference of 25 1/7 inches. What is the area of the cake? Use 22/7 to approximate pi
Novosadov [1.4K]
To calculate for area given the circumference we proceed as follows:
C=2πr
where:
r=radius
thus given that C=25 1/7 in=176/7
thus plugging in our formula to solve for r we get:
176/7=2πr
thus
r=4.002~4.00 in
hence the area will be:
A=πr²
A=π×(4²)
A=50 2/7 in²


7 0
4 years ago
He simultaneous equations<br>5x + y = 21<br>x - 3y = 9 <br><br>With working out​
Elza [17]

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

5x + y = 21 → (1)

x - 3y = 9 → (2)

Multiply (1) by 3 and add the result to (2) to eliminate y term

15x + 3y = 63 → (3)

Add (2) and (3) term by term

(x + 15x) + )- 3y + 3y) = (9 + 63)

16x = 72 ( divide both sides by 16 )

x = 4.5

Substitute x = 4.5 into (1) for corresponding value of y

22.5 + y = 21 ( subtract 22.5 from both sides )

y = - 1.5

Solution is (4.5, - 1.5 )

8 0
3 years ago
What number should be placed in the box to help complete the division calculation. Pls help
ArbitrLikvidat [17]

Answer:

I believe it would be 4

3 0
3 years ago
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