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Delvig [45]
4 years ago
11

What does the expected value of a binomial distribution with n trials tell you?

Mathematics
1 answer:
SVEN [57.7K]4 years ago
3 0

Answer:

The expected value of a binomial distribution with n trials tell us about the the average number of successes

Step-by-step explanation:

A binomial distribution is a frequency distribution of the possible number of successful outcomes in a given number of trials such that there is the same probability of success of each of the outcome.

For n trials with probability of success of each outcome as p, expected value of a binomial distribution  is given by E\left ( X \right )=np .

If we toss 200 coins, and X is the number of heads, the expected value of X is 100= (1/2)200.

So, basically the expected value of a binomial distribution with n trials tell us about the the average number of successes .

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Given:

• Volume of small containers = 2.5 m³

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• Volume of large containers = 4 m³

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• Number of containers in the shipment = 140

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• Total volume = 440 m³

Let's find the number of the size of each container used.

Let s represent the number of small containers

Let L represent the number of large containers.

• Equation for number of containers:

s + L = 140

• Equation for total volume:

2.5s + 4L = 140

Hence, we have the set of equations:

s + L = 140...........................equation 1

2.5s + 4L = 440...................equation 2

Let's solve the set of equations simultaneously using substitution methos.

Rewrite equation 1 for L:

L = 140 - s...........................equation 3

Substitute (140 -s) for L in equation 2:

2.5s + 4(140 - s) = 440

Apply distributive property:

2.5s + 4(140) + 4(-s) = 440

2.5s + 560 - 4s = 440

Combine like terms:

2.5s - 4s + 560 = 440

-1.5s + 560 = 440

Subtract 560 from both sides:

-1.5s + 560 - 560 = 440 - 560

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Divide both sides by -1.5:

\begin{gathered} \frac{-1.5s}{-1.5}=\frac{-120}{-1.5} \\  \\ s=80 \end{gathered}

Substitute 80 for s in either of the equations.

Take equation 3.

L = 140 - s

L = 140 - 80

L = 60.

Therefore, we have the solutions:

s = 80 and L = 60

Therefore, the company used 80 small containers and 60 large containers

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