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2 years ago

What is the solution to the equation below? Round your answer to two decimal places. 3e2x + 12 = 42

Mathematics

1 answer:

Shkiper50 [21]2 years ago

5 0

Answer:

X= 5.52

Step-by-step explanation:

1. Solve the equation:

e×2x + 12= 42

x=15/e

2. Round x=15/e to the required place

x=5.52

You might be interested in

Why is 3/4 greater thab 11/16 how can i be sure

Delicious77 [7]

You can make them have the same denominator and then compare

$( \frac{3}{4}) ( \frac{16}{16}) = \frac{48}{64}$

$(\frac{11}{16})( \frac{4}{4}) = \frac{44}{64}$

so as you can see, $\frac{3}{4} is \frac{4}{64} bigger than \frac{11}{16}$

5 0

3 years ago

Find the slope of the line that passes through the pair of points

professor190 [17]

$Slope= \frac{y_2-y_1}{x_2-x_1} = \frac{-\frac{9}{2} - (-1)}{-2- (-\frac{5}{3})}=\frac{ - \frac{9}{2} + 1}{-2 + \frac{5}{3}} \\= \frac{ - \frac{7}{2}}{ - \frac{1}{3}} \\= \frac{ - \frac{7}{2}\cdot6}{ - \frac{1}{3}\cdot6} \\=\frac{-21}{ -2} \\ =\boxed{\bf{ \frac{21}{2}}}$

So... none of your answers are correct. The correct answer is 21/2.

6 0

3 years ago

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

Sixty photos taken at a photo shoot are in black and white. If this represents 15 percent of the total number of photos taken, w

Oduvanchick [21]

If this represents 15 percent of the total number of photos taken, which equation can be used to find the total number of photos? A. 60×4/15×4 = 240/60.

5 0

3 years ago

Read 2 more answers

Which value of x is the solution of the equation 2(x – 4) + 7 = 3? (a) 1 (b) 6 (c) 2 (d) 0

pav-90 [236]

Answer:

Step-by-step explanation:

2(x - 4) + 7 = 3

2x + 2(-4) + 7 = 3

2x - 8 + 7 = 3

2x - 1 = 3

2x - 1 + 1 = 3 + 1

2x = 4

2x/2 = 4/2

x = 2

Hope this helps!!!

4 0

3 years ago