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3 years ago

I NEED HELP FAST PLEASE HELP !

Mathematics

1 answer:

ankoles [38]3 years ago

6 0

Problem 1) We need exactly one unit tile (the smallest square tile) to fill up the empty space to make a completed rectangle. In this case it would be (x+2)^2 = x^2+4x+4

Problem 2) The answer here is choice B since (x+3)^2 expands out to x^2+6x+9. Tacking on a "-6" will take the +9 down to +3. In other words, x^2+6x+9-6 = x^2+6x+3

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What is the mean absolute deviation of the data set? 12, 15, 7, 4, 9, 10, 9, 6

bearhunter [10]

Here is an example:
Find the MAD of 2,4,6,8 Step 1 : Find the mean of the data : (2+4+6+8) / 4 = 20/5 = 4 Step 2 : Find the distance between each data and mean. Distance between 2 and 5 is 3 Distance between 4 and 5 is 1 Distance between 6 and 5 is 1 Distance between 8 and 5 is 3
Step 3 : Add all the distances : 3+1+1+3 = 8
Step 4 : Divide it by the number of data : 8 / 4 = 2 2 is the average absolute deviation.

3 0

3 years ago

Simplify 3√20/√5 a)25/4 b)6 c)√5/5 d2√3/15

Blizzard [7]

3√20/√5
= 3 √4 √5 / √5
= 3 * 2
= 6

answer is b)6

3 0

3 years ago

A weight clinic recorded the weight lost (in pounds) by each client of a weight control clinic during the last year, and got the

borishaifa [10]

Answer:

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

Step-by-step explanation:

Given the data :

35, 26, 31, 17, 46, 30, 28, 21, 26, 34, 15, 27, 7, 18, 16, 57

Class interval ____, Frequency _ C/frequency

1 - 10 ____________ 1 _________ 1

11 - 20 ___________ 4 _________ 5

20 - 30 __________ 6 _________ 11

31 - 40 ___________3 _________ 14

41 - 50 ___________ 1 _________ 15

51 - 60 ___________ 1 _________ 16

The next to highest frequency group has a frequency of 4 and the highest frequency of 6

Total frequency, n = (1 + 4 + 6 + 3 + 1 + 1) = 16

5 0

3 years ago

Complete the bar models for the steps yo do to solve the problem. Max has 35 trading cards. He buys 22 more cards. Then he gives

choli [55]

He had fourty three more cards left

6 0

3 years ago

A 2.2 kg ball strikes a wall with a velocity of 7.4 m/s to the left. The ball bounces off with a velocity of 6.2 m/s to the righ

Naya [18.7K]

Answer:

The constant force exerted on the ball by the wall is 119.68 N.

Step-by-step explanation:

Consider the provided information.

It is given that the mass of the ball is m = 2.2 kg

The initial velocity of the ball towards left is 7.4 m/s

So the momentum of the ball when it strikes is = $2.2\times 7.4=16.28$

The final velocity of the ball is -6.2 m/s

So the momentum of the ball when it strikes back is = $2.2\times -6.2=-13.64$

Thus change in moment is: $16.28-(-13.64)=29.92$

The duration of force exerted on the ball t = 0.25 s

Therefore, the constant force exerted on the ball by the wall is:

$\frac{29.92}{0.25}=119.68$

Hence, the constant force exerted on the ball by the wall is 119.68 N.

6 0

3 years ago