Answer:
A) 69.08 m
Step-by-step explanation:
C=2πr
C=2π(11)
C=22π
C≈69.12
Since < ABD is a right triangle (with a measure of 90 °), we can establish the formula to solve for the value of x:
Let < BAC = m < 1 = (15x - 2)°
< CAD = m < 2 = (7x + 4)°
Use the formula:
m < 1 + m < 2 = 90°
Substitute the values of m < 1 and 2:
15x - 2 + 7x + 4 = 90°
Combine like terms:
22x + 2 = 90°
Subtract 2 from both sides:
22x + 2 - 2 = 90° - 2
22x = 88°
Divide both sides by 22:
22x/22 = 88/22
x = 4
Now that we have the value of x, we can plug this value into the given angles:
< BAC = m < 1 = (15x - 2)° = 15(4) - 2 = 58°
< CAD = m < 2 = (7x + 4)° = 7(4) + 4 = 32°
m < 1 + m < 2 = 90°
58° + 32° = 90°
90° = 90° (true statement).
Therefore, (15x - 2)° = 58° and (7x + 4)° = 32°.
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Step-by-step explanation:
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Answer:
a. y = 6
b. RS = 44
ST = 37
RT = 81
Step-by-step explanation:
RS = 7y + 2
ST = 5y + 7
RT = 14y - 3
find:
a. y
b. RS, ST, RT
RS + ST = RT
7y + 2 + 5y + 7 = 14y - 3
group like terms
7y + 5y + 2 + 7 = 14y - 3
12y + 9 = 14y - 3
9 + 3 = 14y - 12y
12 = 2y
y = 12/2
y = 6
-----------------------------------
b.
RS = 7(6) + 2
RS = 44
ST = 5(6) + 7
ST = 37
RT = 14(6) - 3
RT = 81
The probability it will rain of Hari Merdeka is 2/15. Since you are finding the probability that will be no rain on Hari Merdeka, you also need to find the part of 15/15 that is not 2/15. You can do this by subtracting.
15/15-2/15=13/15.
The probability that will be no rain on Hari Merdeka is 13/15.