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Hunter-Best [27]
4 years ago
8

A truck can be rented from Company A for $130 a day plus $0.50 per mile. Company B charges $50 a day plus $0.70 per mile to rent

the same truck. How many miles
must be driven in a day to make the rental cost for Company A a better deal than Company B's?
For Company A to have a better deal, the truck must be driven more than miles per day
Mathematics
2 answers:
diamong [38]4 years ago
8 0

Answer:

The charges of both companies will be same if truck is driven 200 miles per day

Company A will have better deal if truck is driven more than 200 miles per day ( because per mile rate of company A is less than company B

Step-by-step explanation:

Let the truck is driven X miles per day

Charges of company A will be = 90+0.4X

Charges of company B will be =30+0.7X

Let us find out value of X when charges of both companies are same

which means that   90+0.4 X= 30+0.7X

                            90-30      = 0.7X-0.4X

                            60    = 0.3X

                             60/0.3 = X

                             X= 200

Damm [24]4 years ago
3 0

Answer:

200 miles

Step-by-step explanation:

hope this helps :)

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Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}

Now, we calculate the sum

\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\

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\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98

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3 years ago
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pantera1 [17]

Here we are given the specific equation of:

amount of eroded soil = 0.4 + 1.3 x

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A linear equation has a general formula in the form of:

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If we compare this with our specific equation, we can see that the slope and y intercept are both positive with values:

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Hence the correlation must be positive but we cannot solve for the exact value since we need the data for x and y.


Answer: 

positive, but we cannot say what the exact value is

4 0
3 years ago
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MissTica

Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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3 0
3 years ago
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