Question

The sum of 5 consecutive integers is 200. What is the fourth number in this sequence.

Answer 1

STEP-BY-STEP SOLUTION:

Let the smallest integer of the five integers = x

x + x + 1 + x + 2 + x + 3 + x + 4 = 200

5x + 10 = 200

5x = 200 - 10

5x = 190

x = 190 / 5

x = 38

Therefore:

Number no. 4 = x + 3 = 38 + 3 = 41

FINAL ANSWER:

Hence, the fourth number in the sequence is 41.

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