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Genrish500 [490]
2 years ago
12

The question "How many servers will be needed to reduce the waiting time of restaurant customers to less than 9 minutes?" is a t

ype of
Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
3 0

The question posed in the task content is a goal seeking analysis type of question.

How many servers will be needed to reduce the waiting time of restaurant customers to less than 9 minutes is a goal seeking analysis question.

<h3>Goal seeking analysis</h3>

A goal seeking analysis question is a type of question which helps to determine the efficient and effective measure of achieving a goal either individually or in a group.

The question will help the manager of the restaurant to determine how many servers is needed in order to reduce the waiting time of customers.

Complete question:

The question "How many servers will be needed to reduce the waiting time of restaurant customers to less than 9 minutes?" is a type of

a. goal-seeking analysis.

b. what-if analysis.

c. sensitivity analysis.

d. utility modeling.

a. goal-seeking analysis.

Learn more about goal:

brainly.com/question/1512442

#SPJ1

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-6(7m + 4) = -108 <br><br> Equations with distribution
enyata [817]

Answer:

m=2

Step-by-step explanation:

4 0
3 years ago
Find the area of the figure below, formed from a triangle and a rectangle, in square centimeters. A figure is formed from a righ
lana [24]
C.44 square centimeters
8 0
3 years ago
What is the overall charge for neon,oxide, copper, and tin ?
Finger [1]

Answer:

Neon is stable, hence has no charge.

Oxide (O2-) has a charge of -2

Cooper (Cu2+) has a charge of +2

Tin (Sn2+) has a charge of +2

hence overall charge = -2+2+2

<em><u>Over</u></em><em><u>all</u></em><em><u> </u></em><em><u>charge</u></em><em><u> </u></em>= +2

6 0
2 years ago
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
PLEASE HELP!!!!! I NEED THIS FAST!!!!!!
ioda
Who says V1=V2?
if we simplify we get
(2/3)pir₁³=12pir₂²
for V1 to equal V2


a.
solve for r₁ to find r₁ as a function of r₂
(2/3)pir₁³=12pir₂²
times 3/2 both sides and divide by pi
r₁³=18r₂²
cube root both sides
r₁=∛(18r₂²)

if solve for r₂
(2/3)pir₁³=12pir₂²
divide by 12pi both sides
(1/18)r₁³=r₂²
squer root both sides
√((1/18)r₁³)=r₂



double radius of pond which is r1
√((1/18)r₁³)=r₂
r₁ turns to 2r₁ to double radius
√((1/18)(2r₁)³)=r₂double
√(8(1/18)(r₁)³)=r₂double
(√8)(√((1/18)(r₁)³))=r₂double
√((1/18)r₁³)=r₂ so
(√8)(r₂)=r₂double
(2√2)(r₂)=r₂double
the radius of the tank is multipled by 2√2
5 0
3 years ago
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