If there were 49 cars in a line that stretched 528 feet, what is the average car length? assume that the cars are lined up bumper-to-bumper
Answer: We are given there are 49 cars
Also these 49 cars are in a line stretched 528 feet.
Now the average length of the car is:
Average length = 
=
Therefore, the average length of car is 10.78 feet
Answer:
1. 14 = 2 + 12
2. 16 = 4 + 12
3. 18 = 6 + 12
4. 20 = 8 + 12
Step-by-step explanation:
Super easy. All you do is replace the numbers in your table with the corresponding letter. In this case we have a table of s and f.
Example for row two: f = s + 12. Replace s with 4 ( 4 is from your s column so you would replace it with that) then solve and plug in your answer (When you solve your answer, it will go under f column).16 = 4 + 12 . f = 16, s = 4.
Formula = f = s + 12.
1. 14 = 2 + 12
2. 16 = 4 + 12
3. 18 = 6 + 12
4. 20 = 8 + 12
Answer:
Step-by-step explanation:
Answer:
A, B, C, E
Step-by-step explanation:
It can be seen from the figure that the points A, B, C and D, all are lying in the line t.
=> So that it can be concluded that AC and BC and BD have the slopes which are equal to each other and also equal to the slop of line t
So that all answer A, B, C are true.
In addition, as FD is parallel with x - axis, so that slope of the line t is equal to <em>tan angel FDB </em>
As FDB is the right triangle with BFD = 90°
=> tan angel FDB = FB/ FD (tan of an acute angel in the right triangle = opposite side/ adjacent side)
=> Slope of the line t is equal to FB/ FD
=> Answer E is true
Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- There are 12 bulbs, hence N = 12.
- 3 are defective, hence k = 3.
The third defective bulb is the fifth bulb if:
- Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
- The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.
Hence:
0.2182 x 1/8 = 0.0273.
0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
