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Tju [1.3M]
3 years ago
14

Please help marking brainliest if correct!!

Mathematics
2 answers:
BlackZzzverrR [31]3 years ago
6 0

Answer:

Step-by-step explanation:

2x=5x+60.

0=3x+60 ( subtract 2x from both sides)

-60=3x(subtract 60 on both sides)

x=-20

Hope this helps plz mark brainliest if correct :D

Masja [62]3 years ago
5 0

Answer:

yeah its correct i just took the test.

Step-by-step explanation:

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A community swimming pool is 90 2/5 feet long and 55 1/2 feet wide. If Natalie swims the perimeter of the pool four times, what
Drupady [299]

Answer:

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3 0
3 years ago
I added a screenshot of my question
Anastasy [175]
<h2>Answer:</h2>

y=\frac{1}{3}x+4

<h2>Explanation:</h2>

Slope-intercept form:

What the variables mean:

Y=the y axis

m=the slope

x=the x-axis

b=the y intercept (the point on the line that crosses the y-axis)

To Calculate the Slope:

1. Find any 2 points on the line

2. The number of units the second point is above the first is the numerator

3. The number of units the second point is to the right of the first is a denominator

(Please see the picture attached)

y=\frac{1}{3}x+b

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y=\frac{1}{3}x+4

5 0
4 years ago
What is the solution to this system of equations? Negative 3 x + 5 y = negative 2. 3 x + 7 y = 26. NEED FAST TAKING UNIT TEST 40
Citrus2011 [14]

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Read 2 more answers
Which definite integral approximation formula is this: the integral from a to b of f(x)dx ≈ (b-a)/n * [<img src="https://tex.z-d
Stella [2.4K]

The answer is most likely A.

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<em>n</em> subintervals require <em>n</em> + 1 points, with

<em>x</em>₀ = <em>a</em>

<em>x</em>₁ = <em>a</em> + (<em>b</em> - <em>a</em>)/<em>n</em>

<em>x</em>₂ = <em>a</em> + 2(<em>b</em> - <em>a</em>)/<em>n</em>

and so on up to the last point <em>x</em> = <em>b</em>. The right endpoints are <em>x</em>₁, <em>x</em>₂, … etc. and the height of each rectangle are the corresponding <em>y </em>'s at these endpoints. Then you get the formula as given in the photo.

• "Average rate of change" isn't really relevant here. The AROC of a function <em>G(x)</em> continuous* over an interval [<em>a</em>, <em>b</em>] is equal to the slope of the secant line through <em>x</em> = <em>a</em> and <em>x</em> = <em>b</em>, i.e. the value of the difference quotient

(<em>G(b)</em> - <em>G(a)</em> ) / (<em>b</em> - <em>a</em>)

If <em>G(x)</em> happens to be the antiderivative of a function <em>g(x)</em>, then this is the same as the average value of <em>g(x)</em> on the same interval,

g_{\rm ave}=\dfrac{G(b)-G(a)}{b-a}=\dfrac1{b-a}\displaystyle\int_a^b g(x)\,\mathrm dx

(* I'm actually not totally sure that continuity is necessary for the AROC to exist; I've asked this question before without getting a particularly satisfying answer.)

• "Trapezoidal rule" doesn't apply here. Split up [<em>a</em>, <em>b</em>] into <em>n</em> subintervals of equal width (<em>b</em> - <em>a</em>)/<em>n</em>. Over the first subinterval, the area of a trapezoid with "bases" <em>y</em>₀ and <em>y</em>₁ and "height" (<em>b</em> - <em>a</em>)/<em>n</em> is

(<em>y</em>₀ + <em>y</em>₁) (<em>b</em> - <em>a</em>)/<em>n</em>

but <em>y</em>₀ is clearly missing in the sum, and also the next term in the sum would be

(<em>y</em>₁ + <em>y</em>₂) (<em>b</em> - <em>a</em>)/<em>n</em>

the sum of these two areas would reduce to

(<em>b</em> - <em>a</em>)/<em>n</em> = (<em>y</em>₀ + <u>2</u> <em>y</em>₁ + <em>y</em>₂)

which would mean all the terms in-between would need to be doubled as well to get

\displaystyle\int_a^b f(x)\,\mathrm dx\approx\frac{b-a}n\left(y_0+2y_1+2y_2+\cdots+2y_{n-1}+y_n\right)

7 0
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