If you lose two lbs a week consuming 600 calories, how many lbs would you lose consuming half of that?
1 answer:
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Answer:
Kristen bought 2 fancy shirts and 5 plain t-shirts.
Step-by-step explanation:
Given that,
Kristen spent $131 on 7 shirts.
Cost of one fancy shirt = $28
Cost of one plain t-shirt = $15
Let,
x be the number of fancy shirts
y be the number of plain t-shirts
x+y = 7 Eqn 1
28x+15y=131 Eqn 2
Multiplying Eqn 1 by 15
15(x+y=7)
15x+15y=105 Eqn 3
Subtracting Eqn 3 from Eqn 2
(28x+15y)-(15x+15y)=131-105
28x+15y-15x+15y=26
13x=26
Dividing both sides by 13
Putting x=2 in Eqn 1
2+y=7
y=7-2
y=5
Hence,
Kristen bought 2 fancy shirts and 5 plain t-shirts.
Alright, lets get started.
We have given angle A = 40°
We are also given angle B is complement of A.
Complementary angles are two angles whose sum is 90, it means
angle B =
angle B =
angle B = 50° Answer
Now given, angle C is supplement of angle B.
Supplementary angles are two angles whose sum is 180°.
Means angle C =
angle C =
angle C = 130° : Answer
Means angle B = 50° and angle C = 130°
Hope it will help :)
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355