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aleksandrvk [35]
3 years ago
7

What ratios are equal to 10:15​

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

It is 2/3

Step-by-step explanation:

Divide 10 and 15 by 5 to get 2:3

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Round 93.0129 to the nearest thousandth
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Answer:

93.013

Step-by-step explanation:

the ansewer is 93.013

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Consider the function p(c)=2^c+1 . What is p(3)? 8 6 9 -8
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im gonna say its 6 but im not so sure. But thats my closest answer

Step-by-step explanation:

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Which of the following slopes of a line passes through points (2, 3) and (4,7) ?
serg [7]

Answer:

2

Step-by-step explanation:

slope = (difference in y)/(difference in x)

slope = (7 - 3)/(4 - 2)

slope = 4/2 = 2

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8 0
3 years ago
How much does 4 5/7 kg of candy cost if 5/6 kg costs $7.50
Aliun [14]

Answer:

It costs $42.43

Step-by-step explanation:

Lets explain how to solve the problem

- The cost of \frac{5}{6} kilogram of candy is $7.5

- We need to find the cost of 4\frac{5}{7} kilogram

We  can use the ratio to find the answer

======= Dollar   :    Kilogram

======= 7.5        :    \frac{5}{6}

=======  c           :    4\frac{5}{7}  

By using cross multiplication

∴ c × \frac{5}{6} = 7.5 × 4\frac{5}{7}

∵ 4\frac{5}{7} = \frac{4*7+5}{7}

∴ 4\frac{5}{7} = \frac{33}{7}

∴ c × \frac{5}{6} = 7.5 × \frac{33}{7}

∴ c × \frac{5}{6} = \frac{495}{14}

Divide both sides by \frac{5}{6}

∴ c = \frac{495}{14} ÷ \frac{5}{6}

Change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∴ c = \frac{495}{14} × \frac{6}{5}

∴ c = \frac{297}{7} = 42.43 dollars

∵ c represents the cost of 4\frac{5}{7} kg

∴ It costs $42.43

7 0
3 years ago
A truck is used to transport gravel. The box on the truck is a rectangular prism 11 ft long, 7 ft wide and 4 ft high. The box do
chubhunter [2.5K]

Answer:

308 cubic feet

Step-by-step explanation:

The box on the truck has dimensions 11 ft by 7 ft by 4 ft.

The volume of the box is:

V = L * W * H

V = 11 * 7 * 4

V = 308 cubic feet

The truck can transport 308 cubic feet of gravel.

8 0
3 years ago
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