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2 years ago

If 2 inches is 5 centimeters, which of following is correct?

1 answer:

4 0

Unit conversion is a way of converting some common units into another without changing their real value. The correct option is D.

<h3>What is unit conversion?</h3>

Unit conversion is a way of converting some common units into another without changing their real value. for, example, 1 centimeter is equal to 10 mm, though the real measurement is still the same the units and numerical values have been changed.

The complete question is mentioned in the below image.

Given that 2 inches are 5 centimeters. Therefore, the ratio of an inch to centimeters are,

2 inches = 5 centimeters

1 inch = 5/2 centimetes

Now, if using the ratio, the measurements are converted then,

A.) 7 inches = 7 × (5/2)centimeters = 17.5 centimetes

B.) 5 inches = 5 × (5/2)centimeters = 12.5 centimetes

C.) 8 inches = 8 × (5/2)centimeters = 20 centimetes

D.) 3 inches = 3 × (5/2)centimeters = 7.5 centimetes

As it can be observed that the correct statement is D If 2 inches is 5 centimeters, then 3 inches is 7.5 centimeters. Hence, the correct option is D.

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A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

$h(t) = -16t^2 + 30t$

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

$f(x) = ax^2 + bx + c$ :

$f(\frac{-b}{2a}) = maximum/minimum$

i.e we first solve for $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for x in $f(x) = ax^2 + bx + c$

In our case:

First we need to solve $\frac{-b}{2a}$

Then substitute $\frac{-b}{2a}$ for t in $h(t) = -16t^2 + 30t$

By comparison:

$b = 30$

$c = -16$

$\frac{-b}{2a} = \frac{-30}{2 * -16}$

$\frac{-b}{2a} = \frac{-30}{-32}$

$\frac{-b}{2a} = \frac{30}{32}$

$\frac{-b}{2a} = \frac{15}{16}$

Substitute $\frac{15}{16}$ for t in $h(t) = -16t^2 + 30t$

$h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})$

$h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}$

$h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}$

$h(\frac{15}{16}) = \frac{-225 + 450}{16}$

$h(\frac{15}{16}) = \frac{225}{16}$

$h(\frac{15}{16}) = 14.0625$

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because $14.0625 < 15$

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