To multiply fractions, the numerator of the product is the product of the numerators, likewise for the denominators.
(2/3) x (4/7) x (14/5) = (2 x 4 x14) / (3 x 7 x 5)
= (112) / (105) = 1 and 1/15 .
The mass of brick is 2478 gram
<em><u>Solution:</u></em>
A brick is in the shape of a rectangular prism with a length of 8 inches, a width of 3.5 inches, and a height of 2 inches
Length = 8 inches
Width = 3.5 inches
Height = 2 inches
<em><u>The volume of rectangular prism is given as:</u></em>
Thus volume of brick is 56 cubic inches
<em><u>Convert inches to centimeter</u></em>
1 inch = 2.54 centimeter
Therefore,
56 cubic inches = 56 x 2.54 x 2.54 x 2.54 cubic centimeter
56 cubic inches = 917.676 cubic centimeter
Thus, we get,
volume = 917.676 cubic centimeter
The brick has a density of 2.7 grams per cubic centimeter
Density = 2.7 grams
<em><u>The mass of brick is given by formula:</u></em>
<em><u>Substituting the values we get,</u></em>
Thus mass of brick is 2478 gram
The answer is A. -2+5i.
First you set up the problem like this: (6+2i)-(8-3i)
Then you distribute the (-) into the second parenthesis. After doing that you should have something that looks like this: 6+2i-8+3i
Then you add like terms.
Answer:
k = (6/15)
Step-by-step explanation:
The equation is:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
To have no solutions, we need to have something like:
x + 7 = x + 4
where we can remove x in both sides and end with
7 = 4
So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.
First, let's try to simplify our equation:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
6*x + 6 + 2 = 3*k*5*x + 3*1 + 3
6*x + 8 = 15*k*x + 6
if 15*k = 6, then the system clerly has no solution.
then:
k = 6/15
then we get:
6*x + 8 = (6/15)*15*x + 6
6*x + 8 = 6*x + 6
8 = 6
The system has no solutions.
Answer:
{-3, -1, 1}
Step-by-step explanation:
Zeros refer to x-intercepts. X-intercepts are x values when y = 0. You can tell where they are by looking at where the line passes the x-axis.
Therefore, {-3, -1, 1} are the zeros.
