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Lilit [14]
2 years ago
8

What is the sum of -4r +1 and 6x - 5 ?

Mathematics
1 answer:
Margarita [4]2 years ago
8 0
There is no answer bc they are expressions
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Which statement describes volume?
devlian [24]

Answer:

Volume is the quantity of three-dimensional space enclosed by a closed surface

Step-by-step explanation:

7 0
3 years ago
Solve the system by graphing x+y=2 and x-3y=18
erik [133]
(6,-4) that’s what I assume

3 0
2 years ago
Find the missing angle. 9 5 x°​
iragen [17]

Answer:

45 degrees

Step-by-step explanation:

the right angle is 90 degrees and one angle is 45 degrees and 90+45=135 and 180-135=45 so 45 degrees is the missing angle

5 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
A private jet flies the same distance in 8 hours that a commercial jet flies in 7 hours. If the speed of the commercial jet was
mamaluj [8]

Solving a system of equations, we can see that:

  • Speed of the private jet: 168 mi/h
  • Speed of the commercial jet: 192mi/h

<h3>How to find the speeds of each jet?</h3>

Let's define the variables:

  • P = speed of the private jet.
  • C = speed of the commercial jet.

With the given information, we can write:

P*8h = D

C*7h = D

C = 2*P - 144mi/h

So we have a system of 3 equations, where D is the distance in the problem.

With the first and second equations we can write:

P*8h = D = C*7h

Isolating P, we get:

P = C*(7/8)

Now we can replace that in the last equation:

C = 2*P - 144mi/h

C = 2*C*(7/8) - 144mi/h

And now we can solve that for C.

C - 2*(7/8)*C = - 144mi/h

C*(1 - 14/8) = -144mi/h

C*(8/8 - 14/8) = - 144mi/h

C*(6/8) = 144mi/h

C = (8/6)*144mi/h = 192mi/h

Now that we know the speed of the commercial jet, we can find the speed of the private jet.

P = C*(7/8) = 192mi/h*(7/8) = 168 mi/h

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

6 0
2 years ago
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