What is the sum of -4r +1 and 6x

At a restaurant, you order an appetizer for $5.25, a meal for $12.75, and a drink for $2.99. If the sales tax is 9%, what is the

Yuliya22 [10]

Answer:

$22.88

Step-by-step explanation:

The total bill is the subtotal plus tax. The tax is computed by multiplying the tax rate by the subtotal, which is the total of all items being billed.

subtotal = $5.25 +12.75 +2.99 = 20.99

tax = $20.99 × 0.09 = $1.89

The total bill is ...

subtotal + tax = $20.99 +1.89 = $22.88

6 0

2 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

What is the area of the parallelogram?

vichka [17]

Opposite sides are equal in length and opposite angles are equal in measure. To find the area of a parallelogram, multiply the base by the height. The formula is: A = B * H where B is the base, H is the height, and * means multiply.

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=8%20a%20b%20%5E%20%7B%202%20%7D%20%3A%206%20a%20%5E%20%7B%202%20%7D%20b" id="TexFormula1" titl

g100num [7]

$\boxed{\large{\bold{\blue{ANSWER~:) }}}}$

$8ab^{2}:6a^{2}b\\\\=\dfrac{8ab^{2}}{6a^2b}\\\\=\dfrac{2×4×a×b×b}{2×3×a×a×b}\\\\=\dfrac{4b}{3a}\\\\=4b:3a$

4 0

3 years ago

Question 7

Anna35 [415]

Answer:

about 9 pounds, 7 ounces

Step-by-step explanation:

5 ounces per week

for 4 weeks

= 5 x 4 = 20 ounces gained thought these 4 weeks

Now add

8 Pounds, 3 ounces + 20 ounces = 9 pounds, 7 ounces

7 0

2 years ago

What is the sum of -4r +1 and 6x - 5 ?