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irina [24]
2 years ago
7

Find the area of the shaded regions.

Mathematics
1 answer:
vlada-n [284]2 years ago
5 0

Answer: 27\pi \text{ cm}^{2}

Step-by-step explanation:

The area of the entire circle is (\pi)(6^{2})=36\pi

The area of the sector with the right angle is \frac{36\pi}{4}=9\pi

Subtracting these areas, we get 27\pi \text{ cm}^{2}

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Tyrone makes a scale drawing of his backyard. The scale from the backyard to the drawing is 2 ft to 1 in. The width of the patio
Sphinxa [80]

Answer:

The width of Tyrone's actual patio is 16 feet

Step-by-step explanation:

\frac{2ft}{1in} =  \frac{x}{8}   If we look at what we know, we see that the scale tells us that 1 inch is proportional to 2 ft.  What do we need to multiple 1 inch by to get 8 inches?  8.  So, we multiply 2 feet by 8 to get the actual size of the patio which is 16 feet.

6 0
1 year ago
Solve equation: –6 + 3x = –9
ICE Princess25 [194]
3x=-9+6
3x=-3
x=-3/3
x=-1
3 0
4 years ago
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PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU BRAINLIEST!!!!!! PLSSS HELPPPP I WILLL GIVE YOU B
natta225 [31]

Answer:

the proifc is true

Step-by-step explanation:

7 0
3 years ago
Can someone help me for this question please? I just keep getting wrong answer! Pls someone explain to me step by step! ASAP!!!
Kobotan [32]

Answer:

  84 feet

Step-by-step explanation:

This problem involves several steps. The first step is to realize that the given figure does not show the required number of vertical stringers. It shows 5, but there will be 7 of them. The given diagram is helpful in that it shows a vertical stringer on the centerline of the arches.

The second step is to write a function that will tell you how long the stringer will be. I find it convenient to write the equation for an arch shape such as this using the parent function h(x) = 1-x^2. This parent function gives an arch of height 1 and width 1 from center (a total width of 2). You want an arch that is 16 ft high and 40 ft wide (one side from center), so you must scale this parent function both horizontally (by 40) and vertically (by 16). It becomes ...

  H(x) = 16(1 -(x/40)^2)

The taller arch is twice this height, so the length of a vertical stringer at position x is

  vertical length = 2H(x) -H(x) = H(x)

That is, the function H(x) we defined can be used to find the length of the stringers.

The third step is to find the stringer lengths. It can save some energy if you realize that the problem is symmetrical, so that the stringer at x=-30 is the same length as the one at x=30. We need to find stringer lengths every 10 feet from -40 feet to +40 feet. Of course, the ones at ±40 feet are zero length, because that is where the two arches meet.

  H(-30) = 16(1 -(3/4)^2) = 7

  H(-20) = 16(1 -(1/2)^2) = 12

  H(-10) = 16(1 -(1/4)^2) = 15

  H(0) = 16

Then the fourth step is to add up the stringer lengths, rounding the result as required.

  7 +12 +15 +16 +15 +12 +7 = 16 + 2(34) = 84 . . . . feet (no rounding needed)

Finally, you need to answer the question asked:

  The sum of vertical stringer lengths is 84 feet.

5 0
3 years ago
The length and breadth of a rectangle are x CM and y CM respectively if the rectangle has an area of 24cm state the possible pai
ELEN [110]

Answer:

The possible pairs of integer values of x and y are  (24 ,1), (12,2), ,(8,3),  and (6,4) .

Step-by-step explanation:

The length of the rectangle = x cm

The breadth of the rectangle = y cm

Area = 24 sq cm

Now,as x and y are both sides of the rectangle so, x and y ARE STRICTLY POSITIVE.

Also,  AREA OF RECTANGLE = LENGTH X BREADTH

⇒ x y  = 24 ,  x >y

So, all possible values of (x,y) =   (24 ,1), (12,2), ,(8,3),  and (6,4)

Hence, for area to be  24 sq units there are 4 possible dimensional sets.

5 0
3 years ago
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