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irina [24]
2 years ago
7

Find the area of the shaded regions.

Mathematics
1 answer:
vlada-n [284]2 years ago
5 0

Answer: 27\pi \text{ cm}^{2}

Step-by-step explanation:

The area of the entire circle is (\pi)(6^{2})=36\pi

The area of the sector with the right angle is \frac{36\pi}{4}=9\pi

Subtracting these areas, we get 27\pi \text{ cm}^{2}

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40 points, please help with all of them
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Answer:

\large\boxed{Q1.\ \text{2 times greater}}\\\\\boxed{Q2.\ J. 3}\\\\\boxed{Q3.\ B. -\dfrac{4}{5}}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Q1.

We have the equation of a line <em>p </em>in the standard form

4x-3y=7

Convert to the slope-intercept form:

4x-3y=7               <em>subtract 3x from both sides</em>

-3y=-4x+7              <em>divide both sides by (-3)</em>

y=\dfrac{4}{3}x-\dfrac{7}{3}

The slope m_1=\dfrac{4}{3}

From the table we have the points (4, 3) and (7, 5). Calculate the slope of line <em>q</em>:

m_2=\dfrac{5-3}{7-4}=\dfrac{2}{3}

Divide the slope of <em>p</em> by the slope of <em>q</em>:

\dfrac{4}{3}:\dfrac{2}{3}=\dfrac{4}{3}\cdot\dfrac{3}{2}=2

Q2.

Parallel line have the same slope. Therefore, if we have the equation of the line in the slope-intercept form, then we have the slope:

y=3x+2\to m=3

Q3.

Parallel line have the same slope.

Calculate the slope from given points (-11, 5) and (-6, 1):

y=\dfrac{1-5}{-6-(-11)}=\dfrac{-4}{-6+11}=\dfrac{-4}{5}=-\dfrac{4}{5}

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Step-by-step explanation:


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Answer:

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Step-by-step explanation:

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Explanation:I sort of made a coordinate graph

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