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1 year ago

Can someone pls help me?

Mathematics

1 answer:

Ilya [14]1 year ago

4 0

Answer:

$\frac{2 ln(5) }{3 ln(2) }$

Step-by-step explanation:

$log_{8}(25) = \frac{ ln(25) }{ ln(8) } = \frac{ ln( {5}^{2} ) }{ ln( {2}^{3} ) } = \frac{2 ln(5) }{3 ln(2) }$

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Solve the simultaneous equations:<br><br> 5x+4y=5<br> 2x+7y=29

OLga [1]

Answer:

x=−3 and y=5

Step-by-step explanation:

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3 years ago

At an university 70% of the students who attend stay on campus. If 1,380 of the students who attend live off campus, what is the

Alborosie

Answer:

4600

Step-by-step explanation:

We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.

$\frac{30}{100}=\frac{1380}{y}$

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

30y=100(1380)

30y=138000

y=4600.

There are 4600 students who attend the university.

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2 years ago

What is the value of x in the equation 150/84 = 25/x

Fofino [41]

Answer:

x = 14

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

population growth problem: the deer population in georgia was 450,000 in 2010, and the population doubles every 5 years. in what

VikaD [51]

We know that in 2020 the population of deer will be 900,000 based on the given numbers. In another 5 years the population will be over 1 million (1,350,000) in order to calculate when it will reach 1 million we need to see how much growth is gained per year. I believe to obtain that information we will need to divide 450,000 by 5 that equals 90,000 a year. So if I’m 2020 the population of deer will be 900,000 than add 90,000 until you reach your 1 million marker. In this case 2021 would be 990,000 thousand so 2022 would be 1,080,000. So your answer should be year 2022. Hope that helps.

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2 years ago

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WINSTONCH [101]

Answer:

x = 20

Step-by-step explanation:

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2 years ago