The answer is c or the third option. If we start at one we get (4(1)-9)=-5, then we can do 2 and we get (4(2)-9)=-1. Lets do 3 (4(3)-9)=3. Now 4 (4(4)-9)=7. Now 5 and our last one (4(5)-9)=11. Now notice we get -5+-1+3+7+11.
Answer:
40
Step-by-step explanation:
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] = ad-bc](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20ad-bc)
Remember: higher risk means you wait less time to get more money.
So I would go with A
Answer:
60%
Step-by-step explanation: