-3(2)(-4)+4(2)-3=24+8-3=29
9514 1404 393
Answer:
y = 4/3x -7
Step-by-step explanation:
The marked points differ in their y-values by +4, and their x-values by 3. The slope of the line is ...
m = rise/run = 4/3
There is a marked point on the y-axis at y = -7. This is the y-intercept. Then the desired equation is ...
y = mx +b . . . . . line with slope m and y-intercept b
y = 4/3x -7
<span>-4n^0 × 3n^-2
= -4(1) </span>× 3n^-2
= -4× 3n^-2
= -12 n^-2
= -12/n^2
Answer: Quadrant iii.
Step-by-step explanation: Given, the measurement of the angle in standard position is -102°. When we are considering negative angles, we will in the clockwise direction. Angles with measurement 0° to -90° will fall in the quadrant iv. Angles measuring -90° to -180° will fall in the quadrant iii. Since -102° lies between -90° and -180°, so, it will be lying in quadrant iii. Please see the attached figure.
Thus, the correct answer is quadrant iii.