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2 years ago

five people arrived at the check _ out counter of a hotel at the same time, in how many different ways can the people line up?

Mathematics

1 answer:

Fantom [35]2 years ago

6 0

There are 120 different ways the people can line up

<h3>How to determine the number of ways?</h3>

The number of people that arrived is:

n = 5

Take the factorial to calculate the number of ways they can line up

n! = 5!

Expand

n! = 5* 4 * 3 * 2 * 1

Evaluate

n! = 120

Hence, there are 120 different ways the people can line up

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Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

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The formula to solve a quadratic equation of the form

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$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

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substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

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$x=\frac{-7(+/-)23} {6}$

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3 years ago

five people arrived at the check _ out counter of a hotel at the same time, in how many different ways can the people line up?​

five people arrived at the check _ out counter of a hotel at the same time, in how many different ways can the people line up?