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jolli1 [7]
3 years ago
15

Help with this math question

Mathematics
1 answer:
Art [367]3 years ago
5 0
Answer: option J: 128 joules

Explanation:

1) From the table you try to find which relation best fits the data.

2) Your best first assumption is that the data may fit a proportional relation.

3) To prove that you find the ratio of Energy ouput to Amount of chemicals.

Doing that you find:
 20        32         48       60
----- =  ------- =  ------ = ------ =  4
  5          8           12      15


4) Then you have found a direct relation whose ratio is 4 joules / mol. So, you can apply that constant to the number of moles given:

Energy = 4  joules / mol × 32 mol = 128 joules
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Mrs. Heath baked 56 cookies. She put an equal number of cookies into 7 bags. How many cookies did she put in each bag?
katen-ka-za [31]

Answer:

8

Step-by-step explanation:

you have to divide 56 by 7 and you will get 8.

6 0
2 years ago
Read 2 more answers
Nonsense will be reported!!​
Contact [7]

Answer:

See below

Step-by-step explanation:

d = 78° (Vertical angles)

h = 70° (Vertical angles)

Measure of angles d and h are are not equal. therefore they are not congruent.

7 0
2 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
Please help me asap i will mark branlist please explain
Ulleksa [173]
It would be b because a^2+b^2=c^2 so in this case 5^2+8^2=c^2
6 0
3 years ago
Can someone help me with this question
Mashcka [7]
The correct answer here would be D. -1(3x+1)(x+5). You can find this answer by redistributing the problem.

-1(3x+1)(x+5)
-1(3x²+15x+1x+5)
-1(3x²+16x+5)
-3x²-16x-5

Using the math above, we can see that when we redistribute we get the original equation. That makes Choice D correct.
5 0
3 years ago
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