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3 years ago

A game is biased such that the choices A-J have the following probabilities of winning:

Mathematics

2 answers:

nirvana33 [79]3 years ago

8 0

Well if you pick D and H then you have a 15% chance of winning out of 20 times which is 3 times

-BARSIC- [3]3 years ago

4 0

Answer:

Step-by-step explanation:

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Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

3 years ago

Dihsjsksiusjsueuuehehebdbbsjsshshshhs

il63 [147K]

is this a real question?

6 0

3 years ago

Manny is covering a book. The front of the book is 11.2 inches high and 7.3 inches wide. What is the area of the front of the bo

irina [24]

Answer:

81.76in^2

Step-by-step explanation:

Given data

Lenght of book= 11.2 inches

WIdth of book= 7.3 inches

We know that Area= Length* Width

Area= 11.2*7.3

Area= 81.76 in^2

Hence the area of the front of the book is is 81.76in^2

7 0

3 years ago

Please Help me with this question will mark as Brainllest

Aleks [24]

Answer:

it is 72

Step-by-step explanation:

8 0

3 years ago

Can you please help me with this, I have no idea

sergejj [24]

I have no clue sorry

6 0

3 years ago