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3 years ago

5

A. write an equation that relates a and b when a = 4 when b = 24

1 answer:

tatiyna3 years ago

3 0

Answer:

a + b = 28

b = 31

Step-by-step explanation:

i hope it's correct but I am not sure tho :)

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Very urgent!!!!!

Zinaida [17]

Answer:

number of terms=9

Step-by-step explanation:

$t_{1}=6\\t_{5}=18\\\\t_{n}=t_{1}+(n-1)d\\18=6+(5-1)d\\18-6=4d\\4d=12\\d=12/4=3\\s_{n}=162\\s_{n}=\frac{n}{2}[2t_{1}+(n-1)d]\\162=\frac{n}{2}[2(6)+(n-1)3]\\162 \times 2=n(12+3n-3)\\324=n(3n+9)\\3n^2+9n-324=0\\n^2+3n-108=0\\n^2+12n-9n-108=0\\n(n+12)-9(n+12)=0\\(n+12)(n-9)=0\\n=-12,9\\n=-12 (rejected)$

as number of terms can't be negative.

6 0

3 years ago

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Write the equation of the line in slope intercept form:

Alina [70]

I hope this helps you

7 0

3 years ago

∠DGC and ∠CGB are □ angles.Adjacent<br> Adjacent<br> Complementary<br> Supplementary<br> Vertical

Andrews [41]

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5 0

3 years ago

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(n2+11n+25) ÷ ( n+5) long division

zmey [24]

Answer:

$(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,R5$

Step-by-step explanation:

<u>Synthetic division:</u>

-5 | 1 11 25

____<u>-5 -30</u>

1 6 | -5

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

<u>Long division:</u>

n+5 | n² + 11n + 25

- <u>n² + 5n____</u> <-- n

6n + 25

- <u> 6n + 30</u> <-- 6

-5 | n+6

Therefore, $(n^2+11n+25)\div( n+5)=n+6-\frac{5}{n+5}$ or $n+6,_$R$5$

6 0

3 years ago

Which pairs of expressions are equivalent <br><br> More the 1 answer

tia_tia [17]

Answer:

The first 3 pairs of expressions are equivalent.

Step-by-step explanation:

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3 years ago