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igor_vitrenko [27]
1 year ago
6

PLEASE I NEED THE ANSWER QUICKLY

Mathematics
2 answers:
Pavlova-9 [17]1 year ago
7 0

Answer:

x = 12 half page advertisements

y = 8 full page advertisements

Step-by-step explanation:

42x + 86y = 1192

x + y = 20

y = 20 - x

Input (20-x) as y into the first equation

42x + 86(20-x)=1192

42x + 1720 - 86x = 1192

(42x - 86x) 1720 -1720= 1192-1720

-44x = -528

x = 12

12 + y = 20

y=8

enot [183]1 year ago
5 0

a. 'x' represents half page advertisement and 'y' represents full page advertisement.

System of equation is given by 42x + 86y = 1192 , x + y =20.

b. Number of full page advertisement  Kathryn purchase is equals to 8.

c.  Number of half page advertisement  Kathryn purchase is equals to 12.

<h3>What is system of equation?</h3>

" System of equation is defined as the finite set of equations for which we find a common solution."

According to the question,

Cost of half page advertisement = $42

Cost of full page advertisement = $86

Number of advertisement Kathryn could purchase = 20

Total budget of Kathryn to purchase advertisement = $1192

'x' represents half page advertisement

'y' represents full page advertisement

As per the situation given system of equation we have,

42x + 86y = 1192                                 ______(1)

x + y = 20                        

x = 20 - y                                             _____(2)

Substitute the value of 'x' from  system of equation (2) in (1) we get,

42( 20 -y) +86y =1192\\\\\implies 840 - 42y +86y =1192\\\\\implies 44y = 1192-840\\\\\implies y = \frac{352}{44}\\ \\\implies y =8

Substitute the value of y in (2) to get 'x' ,

x=20-8

  = 12

Hence,

a. 'x' represents half page advertisement and 'y' represents full page advertisement.

System of equation is given by 42x + 86y = 1192 , x + y =20.

b. Number of full page advertisement  Kathryn purchase is equals to 8.

c.  Number of half page advertisement  Kathryn purchase is equals to 12.

Learn more about system of equation here

brainly.com/question/13997560

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Step-by-step explanation:

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In △ABC, point D∈AC
Maslowich
<h3>Answer:</h3>
  • ABDC = 6 in²
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<h3>Explanation:</h3>

A diagram can be helpful.

When triangles have the same altitude, their areas are proportional to their base lengths.

The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...

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so ABDC will be 6/5 times AEDC.

... ABDC = (6/5)×(5 in²)

... ABDC = 6 in²

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The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...

... AABD : ABDC = AD : DC = 4 : 3

so AABD will be 4/3 times ABDC.

... AABD = (4/3)×(6 in²)

... AABD = 8 in²

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Of course, AABC is the sum of the areas of the triangles that make it up:

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In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?
erica [24]

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

BD = c*sin(A)

BD = c*cos(B)

BD = b*tan(A)

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

sin(A) = \frac{x}{c}

Make x the subject of formula.

c*sin(A) = x

BD = x = c*sin(A)

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

cos(B) = \frac{x}{c}

Make x the subject of formula.

c*cos(B) = x

BD = x = c*cos(B)

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

tan(A) = \frac{x}{b}

Make x the subject of formula.

b*tan(A) = x

BD = x = b*tan(A)

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