Given:
The function is
To find:
The inverse of the given function.
Solution:
We have,
Substitute m(x)=y.
Interchange x and y.
Add square of half of coefficient of y , i.e., on both sides,
Taking square root on both sides.
Add on both sides.
Substitute .
We know that, negative term inside the root is not real number. So,
Therefore, the restricted domain is and the inverse function is .
Hence, option D is correct.
Note: In all the options square of is missing in restricted domain.
Do you want a proof or just the answer?
The answer is: the square (2.5x2.5).
It hits the ground at h=0
0=-16t^2-16t+96
undistribute -16
0=-16(t^2+t-6)
factor
0=-16(t-2)(t+3)
set to zero
0=t-2
2=t
t+3=0
t=-3, nope, we can't have negative time
at t=2, or 2 seconds
The schools is loacted at <u>(1, -8)</u> and the park is loacted at <u>(-6,-8)</u>
To solve for the time an object takes to hit the ground, the equation
<em>y</em> <em>= y₀ + v₀t + ½gt²</em>, or just <em>0 = y₀ +½gt²</em> since there is no initial velocity and the final y position is 0 (since it is on the ground). Therefore, <em>t = (−2y₀/g)^½.</em>
(-2*60/-9.8)^½ = 3.50 seconds.
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