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3 years ago

Which number is largest? A. 0.78 B. 3/10 C. 0.50 D. 82/100

Mathematics

2 answers:

Olegator [25]3 years ago

7 0

C. 0.50.

I believe that is the answer. Hope this helped! Sorry if I’m wrong.

-Bella :)

morpeh [17]3 years ago

3 0

Answer:

Step-by-step explanation:

It comes out to .82 which means it's the biggest.

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How do you do this!???

german

Answer:

x=2

Step-by-step explanation:

assuming this shape is euclidean (don't pay attention to this just some extra info, assume that all triangles on a sheet of paper have angles summing to 180)

The sum of all angles in a triangle is 180, so

90+60+15x=180

150+15x=180

15x=30

x=2

5 0

2 years ago

I need help on this problem!!! please help!!!

MA_775_DIABLO [31]

(0.1x-22)+(0.3x-54)=90

First combine like terms

0.4x - 76 = 90

Now add 76 on both sides

0.4x = 166

Divide by 0.4 on each side to isolate x

X= 415

7 0

3 years ago

find the value of x2 values that separate the middle 90% from the rest of the distribution for 8 degrees of freedom

Anettt [7]

Answer:

With alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

Step-by-step explanation:

The significance level ∝ = 1- 0.9 = 0.1

But we need the area of the middle so we divide this significance level with 2

so that we get exactly the middle area .

Dividing 0.1/2= 0.05

So we will have two values for chi square

One with 0.9 + 0.05 = 0.95 alpha and one with 0.05 alpha . This is because the chi square is right tailed.

So with alpha 0.95 and 8 degrees of freedom χ²= 2.73

And with alpha 0.05 and 8 degrees of freedom χ²=15.51

This can be shown with a graph.

4 0

3 years ago

Is sin theta=5/6, what are the values of cos theta and tan theta?

mina [271]

let's bear in mind that sin(θ) in this case is positive, that happens only in the I and II Quadrants, where the cosine/adjacent are positive and negative respectively.

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{hypotenuse}{6}}\qquad \impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{6^2-5^2}=a\implies \pm\sqrt{36-25}\implies \pm \sqrt{11}=a \\\\[-0.35em] ~\dotfill$

$\bf cos(\theta )=\cfrac{\stackrel{adjacent}{\pm\sqrt{11}}}{\stackrel{hypotenuse}{6}} \\\\\\ tan(\theta )=\cfrac{\stackrel{opposite}{5}}{\stackrel{adjacent}{\pm\sqrt{11}}}\implies \stackrel{\textit{and rationalizing the denominator}~\hfill }{tan(\theta )=\pm\cfrac{5}{\sqrt{11}}\cdot \cfrac{\sqrt{11}}{\sqrt{11}}\implies tan(\theta )=\pm\cfrac{5\sqrt{11}}{11}}$

5 0

3 years ago

Help me plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz tired

LenKa [72]

So, y-intercept is (0,3) and x-intercept is (3/7,0)

Step-by-step explanation:

We are given:

$y=-7x+3$

We need to find y-intercept and x-intercept

Finding y-intercept

To find y-intercept we put x =0

Solving:

$y=-7x+3\\y=-7(0)+3\\y=3$

So, y-intercept is (0,3)

Finding x-intercept

To find x-intercept we put y =0

Solving:

$y=-7x+3\\0=-7x+3\\-7x=-3\\x=-3/-7\\x=3/7$

So, x-intercept is (3/7,0)

So, y-intercept is (0,3) and x-intercept is (3/7,0)

Keywords: x and y intercepts

Learn more about x and y intercepts at:

#learnwithBrainly

6 0

3 years ago