800×0.14=112
112+15=127
(127÷800)*100==15.88%
The statement <span>The coefficient of x^k y^n-k in the expansion of (x+y)^n equals (n-k / k) is true. This will show the standard formula and the expansion of it. We all know that it can still be expanded based on the power or degree of the terms.</span>
Answer:
24
Step-by-step explanation:
f(x)=5x^2-7x
substitute x to 3
f(3)=5(3)^2-7(3)
f(3)=5(9)-21
f(3)=45-21
f(3)=24
800.000+60.000+3.000+100+40+1
Since its roots are -4 and 2 and a = 1 [The coefficient of x^2] we know that x^2 + bx + c = (x - (-4)) (x-2)=(x+4)(x-2) = 0. Using the distributive property we get, x^2 + 2x - 8 = 0. By equating coefficients (common strategy for partial fractions and undetermined coefficient method of solving ODE), we get b = 2 and c = -8.
Hope this helps :) If you spot a mistake in my work or have a question comment down below.
