Answer:
True
Explanation:
It is true that a federal tribunal can hear or solve a particular conflict by referring to the concept of justiciability. Justiciability is a term in law that refers to the limits upon legal issues over which a court can exercise its judicial authority. In other words, justiciability establishes the situations when a particular court can exercise its duties. When a court cannot provide an adequate solution to a dispute, the matter is considered not justiciable.
McCulloch v. Maryland (1819) is a historic court case that determined that the necessary and proper clause gave congress the implied power to enact legislation necessary to carry out the powers granted to them.
In the case of McCulloch v. Maryland (1819), the Supreme Court came to the conclusion that the state of Maryland did not have the authority to levy taxes against the Second Bank of the United States. This was due to the fact that Congress had implied powers under the Necessary and Proper Clause of Article I, Section 8 to construct the Bank.
With what is perhaps Chief Justice John Marshall's strongest decision, McCulloch rejected the extreme states' rights arguments made by counsel for Maryland in resounding language while simultaneously giving Congress vast discretionary ability to effectuate the enumerated powers.
This result gave rise to the idea of Congress' implied authority in the Constitution, which holds that Congress has powers beyond those expressly enumerated in the United States Constitution, including powers that may assist such authorities in carrying out those expressly enumerated in the Constitution.
Learn more about McCulloch v. Maryland (1819)- brainly.com/question/20593754
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v