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Oksi-84 [34.3K]
2 years ago
8

If P(n) and Q(n) are polynomials of degree j and k, respectively, then the series

Mathematics
1 answer:
Naya [18.7K]2 years ago
6 0

Answer:

converges

Step-by-step explanation:

well the two polynomials in the series are 1 and n^8 (I'm assuming the +7 is not in the decimal but it seems to not matter). The degree of the polynomial 1 is 0 which can be represented by 1x^0. The second polynomial in the denominator has a degree of 8. So j = 0  and k = 8. Since 0 < (8-1)

0 < 7 the series converges

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<em>P( 73 < x < 84 ) = 0.02145 = 2.1 %</em>

<u>Step-by-step explanation</u>:

<u><em>Explanation</em></u>:-

Given mean of the Population 'μ ' = 51 months

Standard deviation of the Population 'σ' = 11 months

Let 'X' be the random variable of Normal distribution

<em>Let    'X'  = 73</em>

<em></em>Z = \frac{x-mean}{S.D} = \frac{73-51}{11} = 2<em></em>

<em>Let  'X' = 84</em>

<em></em>Z = \frac{84-51}{11} = 3<em></em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 )      = P( 2 < Z < 3)</em>

<em>                               = P( Z<3) - P( Z <2)</em>

<em>                              =  0.5 + A(3) - ( 0.5 + A(2))</em>

<em>                             = A(3) - A( 2)</em>

<em>                             = 0.49865 - 0.4772     ( From Normal table)</em>

<em>                             = 0.02145</em>

<em>  P( 73 < x < 84 ) = 0.02145</em>

<em>The approximate percentage of cars that remain in service between 73 and 84 months</em>

<em>P( 73 < x < 84 ) = 0.02145 = 2.1 %</em>

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