The base is 16 and height of each triangle is 2
Hello :
f(x) = 4(x2 − 6x + 3² - 3²____) + 20 = 4((x2 − 6x + 3²) - 3²____) + 20<span>
= 4(x-3)² -36+20
</span>f(x) = 4(x-3)² -16 (vertex form)
(r+b-g)(b-g)
I this question , we have the values of r,b and g given , which are r=9,b=5,g=6
And we have to find the value of the given expression . And for that we need to substitute the values of r,b and 9 in the expression. That is ,
(9+5-6)(5-6) = 8(-1) = -8
So the value of the given expression is -8.
Answer would be 3/5 (filler)
Basically you substitute 16 in for x.
f(16) = 3/4(16) - 5
f(16) = 12 - 5
f(16) = 7
