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gavmur [86]
3 years ago
5

If r=9, b=5, and g=6. what does (r+b-g)(b-g) equal?

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0

(r+b-g)(b-g)

I this question , we have the values of r,b and g given , which are r=9,b=5,g=6

And we have to find the value of the given expression . And for that we need to substitute the values of r,b and 9 in the expression. That is ,

(9+5-6)(5-6) = 8(-1) = -8

So the value of the given expression is -8.

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Step-by-step explanation:

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5 0
3 years ago
Please helppp me!!!!!
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Answer:

Step 2 contains error in the given problem.

Step-by-step explanation:

Given expression is:

\frac{1}{2}x-3=\frac{1}{3}x+6

Step 1: identifying the LCM.

The LCM identified is 6.

This step is correct.

In the next step, we multiply the LCM with each term of the equation.

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\frac{6}{1}(\frac{1}{2}x) -3 =\frac{6}{1}(\frac{1}{3}x)+6

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Step 2 contains error in the given problem.

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Carisssa's favorite cereal box is 14.5 inches tall 9.5 inches wide and 1.5 inched deep. What is the volume of the cereal box?
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3 0
3 years ago
Rewrite the slope intercept equation of the line y=1/3x-2 in standard form
kaheart [24]
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7 0
4 years ago
Which equation represents the circle described?
bazaltina [42]

We have the equation:

x^2+y^2-8x-6y+24=0


By arranging this equation in terms of x and y, we have:


x^2-8x+y^2-6y=-24 \\ \\


By using the method of completing the square, we have:

x^2-8x+\mathbf{\left(\frac{8}{2}\right)^2}+y^2-6y+\mathbf{\left(\frac{6}{2}\right)^2}=-24+\mathbf{\left(\frac{8}{2}\right)^2}+\mathbf{\left(\frac{6}{2}\right)^2} \\ \\ x^2-8x+\mathbf{16}+y^2-6y+\mathbf{9}=-24+\mathbf{16}+\mathbf{9} \\ \\ \boxed{(x-4)^2+(x-3)^2=1}


The center of this circle is:

(h,k)=(4,3)


So the equation that fulfills the statement is:

(x-4)^2+(y-3)^2=2^2


Finally, the right answer is c)

6 0
3 years ago
Read 2 more answers
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