Question

James needs to mix a 10% acid solution with a 50% acid solution to create 100 milliliters of a 26% solution. How many milliliters of each solution must James use?
James must mix _____ milliliters of 10% solution and____milliliters of 50% solution.

Answer 1

James must mix 60 millilitres of 10% solution and 40 millilitres of 50% solution.

Given that, James needs to mix a 10% acid solution with a 50% acid solution to create 100 millilitres of a 26% solution.

Let the acid solution needs to mix with 10% be x ml and the acid solution needs to mix with 50% will be 100 - x ml.

Now,

10% x + 50% ( 100 - x ) = 26% ×100

⇒$\frac{10x}{100} +\frac{50(100-x)}{100}=\frac{2600}{100}$

⇒10x + 50( 100 - x ) = 2600

⇒10 x + 5000 - 50x = 2600

⇒10 x - 50 x = 2600-5000

⇒-40 x = -2400

⇒x=60

Therefore, James must mix 60 millilitres of 10% solution and 40 millilitres of 50% solution.

To learn more about the percentage visit:

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