You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
So basically here is the answer mate!
2x + 7y = 3-------------------------(substitute x's value here, i.e., x = -4y)
2( -4y ) + 7y = 3
-8y + 7y = 3
-1y = 3
y = -3------------------------( 1 )
Since x = -4y
= -4 ( -3 ) --------------------------( since we found the value of y)
= 12
Here is the answer for x = 12 , y = -3
Mark my anwer as the brainliest please ! :)
Answer:
the answer for this question 1200
Step-by-step explanation:
It's 3.74 rounded up to 4 the reason why it is that answer is because the formula to a triangle's Hypotenuse is A squared + B squared = C squared
Answer:
i believe d. I could be wrong
Step-by-step explanation:
