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ddd [48]
2 years ago
11

What do you think are the most important risks and benefits of modern agricultural practices? Do you think the benefits outweigh

the risks?
Biology
1 answer:
sasho [114]2 years ago
4 0

<h2>Howdy, </h2>

FiRsT PaRt of The QuEsTiOn:

The Risks of Modern agricultural practices are-
contributes to a number larger of environmental issues that cause environmental degradation including: climate change, deforestation, biodiversity loss, dead zones, genetic engineering, irrigation problems, pollutants, soil degradation, and waste.

The benefits of Modern Agricultural practices are-
An increase in yield of primary crops and lower food prices is as the result of modern technology like new crop varieties, the use of big data and precision agriculture.

Modern machinery like tractors and threshers when used up in farming make ploughing and harvesting faster.

SeCoNd PaRt Of ThE QuEsTioN:

No, I don't think the Benefits outweigh the RISKS of hurting the nature because we are compromising the needs of the future for more yield of crops. Modern practices may give you faster results but it takes away the fertility of the soil instead, It makes the land infertile. After using these modern practices you may not even have the land to do agriculture with.  

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Suppose that life exists elsewhere in the universe. all life must contain some type of genetic information, but alien genomes mi
Snowcat [4.5K]
<span>While alien genomes may be constructed by completely different molecules (for example, silicon based life forms are a possibility rather than carbon) it is logical to assume that all life forms would have some sort of protective mechanism to prevent the degradation of DNA during replication. Essentially, to prevent mutations and rapid aging, DNA, alien or otherwise, would have some types of telomeres. They might either be long chains of repeated or irrelevant code or molecules that would not be easily corrupted.</span>
3 0
3 years ago
Select ALL the correct answers.
tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}

10th\ run = 9

So:

B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

Required

Select all true statements

(a) & (d) Median Comparisons

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}                         B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

n = 9                                                         n = 10

Arrange the data:

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

                               Median = \frac{n + 1}{2}th

Median = \frac{9 + 1}{2}th                            Median = \frac{10 + 1}{2}th

Median = \frac{10}{2}th                              Median = \frac{11}{2}th

Median = 5th                                 Median = 5.5}th --- average of 5th and 6th

Median = 2                                    Median = \frac{2+2}{2} = 2

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

n = 9                                                         n = 10

First, calculate the lower quartile (Q1)

Q_1 = \frac{n + 1}{4}th[Odd n]             Q_1 = \frac{n}{4}th [Even n]

Q_1 = \frac{9 + 1}{4}th                            Q_1 = \frac{10}{4}th

Q_1 = \frac{10}{4}th                              Q_1 = 2.5

Q_1 = 2.5th                              

This means that:

Q_1 = 2nd + 0.5(3rd - 2nd)              Q_1 = 2nd + 0.5(3rd - 2nd)

Q_1 = 1 + 0.5(1- 1)                   Q_1 = 1+ 0.5(1 - 1)                      

Q_1 = 1                                       Q_1 = 1

Next, calculate the upper quartile (Q3)

Q_3 = \frac{3}{4}(n + 1)th [Odd n]             Q_3 = \frac{3}{4}(n)th [Even n]

Q_3 = \frac{3}{4}(9 + 1)th                            Q_3 = \frac{30}{4}th

Q_3 = \frac{30}{4}th                                     Q_3 = 7.5th  

Q_3 = 7.5th                                    

This means that:

Q_3 = 7th + 0.5(8th- 7th)           Q_3 = 7th + 0.5(8th- 7th)

Q_3 = 2 + 0.5(3- 2)                       Q_3 = 2+ 0.5(4 - 2)                      

Q_3 = 2.5                                       Q_3 = 3

The interquartile range is  IQR = Q_3 - Q_1

So, we have:

IQR = 2.5 - 1                  IQR = 3 - 1

IQR = 1.5                       IQR  =2

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0
3 years ago
1. Excretion is the process of (1 point)
ycow [4]
Q1. The answer is removing metabolic wastes from the body.
Excretion is the process through which metabolic wastes are removed from the body. Skin, lungs, and greatly kidney, which are the part of the excretory system, are responsible for excretion of metabolic waste in vertebrates. Invertebrates have special systems (insects, for example, have Malpighian tubules) or use skin to excrete metabolic wastes while single-celled organisms use the whole surface of the cell.

Q2. The answer is some animals live in dry or salty environments.
Kidneys are important organs in maintaining water balance. Some animals that live in dry and salty environments must preserve water in order to maintain homeostasis. They drink and eat food with more salt in it. If they lose that precious water in such conditions, the amount of different salts in the organism will increase and it will affect a normal functioning of the organism.

Q3. The answer is simple diffusion across the skin. 
Ammonia is very toxic substance and a lot of water is needed for its neutralisation and excretion. Therefore, animals that live in water excrete ammonia directly in the water. Many freshwater invertebrates eliminate ammonia through skin. In animals that do not live in the water, kidneys and liver help conversion of ammonia into urea which is then excreted.,

Q4. They both actively pump salt across their gills. 
Both saltwater and freshwater fishes use gills to eliminate nitrogenous wastes while kidneys have a little role in the elimination of this kind of the waste. Salt that is lost is replaced by active transport of salt ions into the body by the gills.

Q5. The answer is They both convert nitrogenous wastes to uric acid. 
A garden spider and a sparrow are terrestrial organisms. They do not live in the water and do not excrete metabolic wastes in the water. It is known that ammonia is toxic nitrogenous substance and a lot of water is needed for its excretion. For water organisms this is not a problem, they are surrounded by water, but terrestrial organisms, such as the garden spider and the sparrow, have no such amount of water in the environment, so their kidneys and liver must convert ammonia into urine which can then easily be excreted.
8 0
3 years ago
Función del sistema Nervioso
Alex787 [66]

Answer:

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3 0
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