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Nutka1998 [239]
2 years ago
6

HELP PLEASE. 3(2x+3)=15​

Mathematics
2 answers:
pantera1 [17]2 years ago
7 0

If you are  solving for X then we have to do a few process

What you would want most is to remove the parentheses, so to do that i would use distributive property

3*2x is 6x and 3*3 is 9  so our new equation will look like

6x+9=15 if you don't understand please tell me

now we must bring the 9 over

If you bring the 9 over than it would become negative

6x=15-9

so 6x=6

and now you can solve the answer is x=1

Margarita [4]2 years ago
7 0
Its x=1 bc yeah nd yeah
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2 1/8 divided by 2 =
muminat
⇒ Solutions 

Make mixed fraction to improper fraction 
= 17/8 + 2/1

Make same denominators 
<span>= ((17 × 1) + (2 × 8)) / (8 × 1) </span>

Simplify 
= (17 + 16) / 8

Simplify (17 + 16) / 8<span> </span>
= 33/8

Mixed Fraction 
= 4 1/8
4 0
4 years ago
Read 2 more answers
X – 10x = 100
Mkey [24]

Answer:

x-10x=100

-9x=100

-9x÷-9=100÷-9

x=-11,1

7 0
3 years ago
Kevin bought 3 dvds for 45.99 how much would 7 dvds cost?
Alecsey [184]

Answer:

I am pretty sure the answer would be $107.31. Sorry if I'm wrong.

Step-by-step explanation:

First you take the total of the 3 DVD's (45.99) and you divide that by 3 (number of DVD's) to get 15.33 which is called the unit price. Then, you take your unit price and multiply that by how many items you are going to buy.

45.99 / 3 = 15.33

15.33 x 7 = 107.31

6 0
3 years ago
Raina must choose a number between 55 and 101 that is a multiple of 2, 8 and 10. Write all the numbers that she could choose. If
Aleonysh [2.5K]

Answer:

The only possible number is 80.

Step-by-step explanation:

The number in question needs to be a multiple of all three of 2, 8, and 10. As a result, it must also be a multiple of the least common multiplier (lcm) of the three number.

Start by finding the least common multiplier of the three numbers.

Factor each number into its prime components:

  • 2 is a prime number itself.
  • 8 = 2^3.
  • 10 = 2 \times 5.

The only prime factors are 2 and 5.

  • The greatest power of 2 among the three numbers is 3.
  • The greatest power of 5 among the three numbers is 1.

Therefore, the least common multiplier of the three number should be the product of 2^3 and 5. That's equal to 2^3 \times 5 = 8 \times 5 = 40.

In other words, the number (or numbers) in question could be written in the form 40\, k, where k is an integer.

The question requires that this number be between 55 and 101. In other words,

55 \le 40\, k \le 101.

The goal is to find the possible values of k. Note that from integer division by 40,

  • 55 = 1 \times 40 + 15, and
  • 101 = 2 \times 40 + 21.

The inequality becomes:

1 \times 40 + 15 \le 40\, k \le 2 \times 40 + 21.

However,

  • 1 \times 40 < 55 = 1 \times 40 + 15, and
  • 2 \times 40 + 21 = 101 < 3 \times 40.

Hence,

1 \times 40 < 1\times 40 + 15 \le 40\, k \le 2 \times 40 + 21 < 3 \times 40.

1 \times 40 < 40\, k < 3 \times 40.

Divide by the positive number 40 to obtain:

1 < k < 3.

Since k is an integers, k = 2.

Indeed, 40 \, k = 80 is between 55 and 101.

Therefore, 80 is the number in question.

5 0
4 years ago
Read 2 more answers
What is the slope of the line joining (8, 1) and (24, 9)?
xxMikexx [17]
A that’s what I got
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4 years ago
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