Let the wire left be x yards.
Therefore, the answer of your question will be x yards.
Answer = x yards
Answer: Length = 15 meters
Width = 2 meters
Step-by-step explanation:
Perimeter of a rectangle = 2l + 2w
Area of a rectangle = l × w
where l = length
w = width
Therefore,
2l + 2w = 34 ...... i
l × w = 30 ........ ii
From equation i
2l + 2w = 34
Divide through by 2.
l + w = 17 ...... iii
Then, l = 17 - w ........ iv
Put equation iv into ii
l × w = 30
(17 - w) × w = 30
17w - w² = 30
w² - 17w + 30 = 0
w² - 15w - 2w + 30 = 0
w(w - 15) - 2(w - 15) = 0
(w - 2) = 0
w = 0 + 2 = 2
w - 15 = 0
w = 0 + 15 = 15
Length = 15 meters
Width = 2 meters
Answer:
k = 4/5
Step-by-step explanation:
First, rewrite 5/6k as (5/6)k; this is "five sixths of the variable k."
Next, identify the LCD. It is 6. Then the given equation becomes
5k + 4 = 8
Consolidate the constant terms:
5k = 4
Solve for k: k = 4/5
A - 1766! I hope this helps
Jnjjtyyyuuuuuuuuuuuuuuuuu
