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RSB [31]
3 years ago
12

If f(x) = 5x – 1, then f^-1(x)=

Mathematics
1 answer:
adell [148]3 years ago
3 0

Step-by-step explanation:

f(x) = 5x – 1

To find the inverse equate f(x) to y

That's

f(x) = y

y = 5x - 1

Interchange the terms

x = 5y - 1

Make y the subject

we have

5y = x + 1

Divide both sides by 5

y = x+1/5

Therefore f^-1(x)= x + 1/5

Hope this helps you

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. Find the inverse of the function below on the given interval and write it in the form yequalsf Superscript negative 1 Baseline
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Answer:

The inverse of the function is f^{-1}(x)=\frac{x-5}{3}.

Step-by-step explanation:

The function provided is:

f (x)=3x+5

Let f(x)=y.

Then the value of <em>x</em> is:

y=3x+5\\\\3x=y-5\\\\x=\frac{y-5}{3}

For the inverse of the function, x\rightarrow y.

⇒ f^{-1}(x)=\frac{x-5}{3}

Compute the value of f[f^{-1}(x)] as follows:

f[f^{-1}(x)]=f[\frac{x-5}{3}]

               =3[\frac{x-5}{3}]+5\\\\=x-5+5\\\\=x

Hence proved that f[f^{-1}(x)]=x.

Compute the value of f^{-1}[f(x)] as follows:

f^{-1}[f(x)]=f^{-1}[3x+5]

               =\frac{(3x+5)-5}{3}\\\\=\frac{3x+5-5}{3}\\\\=x

Hence proved that f^{-1}[f(x)]=x.

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3 years ago
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Answer:

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Firstly we find the mean and standard deviation of the given data set.

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Standard deviation(\sigma) = \sqrt{\frac{1}{n}\sum_{i=1}^{n}{(x_{i}-\bar{x})^{2}} }

where, \bar{x} is mean of the distribution.

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Applying t- test:

Let out hypothesis is:

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Here, μ = Population Mean = 4.35

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