Question

Perform the indicated operation and write the answer in the form a + bi. (3 +81) (4-3i)

Answer 1

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: 36 + 23 i$

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$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: (3 + 8i)(4 - 3i)$

$\qquad \tt \rightarrow \: (3 \sdot 4)+ (3 \sdot - 3i) + (8i \sdot4) + (8i \sdot - 3i)$

$\qquad \tt \rightarrow \: 12 - 9i + 32i - (24 {i}^{2} )$

$\qquad \tt \rightarrow \: 12 + 23i -( 24 \sdot - 1)$

$\qquad \tt \rightarrow \: 12 + 23i + 24$

$\qquad \tt \rightarrow \: 36 + 23i$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer 2

SOLVING

$\Large\maltese\underline{\textsf{A. What is Asked \space}}$

Perform the indicated operation and write the answer with the form a+bi.

2 numbers given, one of which is complex

$\Large\maltese\underline{\textsf{B. This problem has been solved!\space\space}}$

Multiply these two numbers, just like you always multiply binomials.

$\bf{(3+8i)(4-3i)}$ | multiply

$\bf{3\times4+3\times(-3i)+8i\times4+8i\times(-3i)}$ | simplify

$\bf{12-9i+32i-24i^2}$ | this can be simplified A LOT

$\bf{12+23i-24i^2}$  | as strange as it may seem, this can be simplified even  more, because isn't i^2 the same as -1?

$\bf{12+23i-24\times(-1)}=12+23i+24}$ | add 12 and 24

$\bf{36+23i}$

$\rule{300}{1.7}$

$\bf{Result:}$

                     $\bf{=36+23i}$. The answer is written in the form a+bi, as requested.

$\boxed{\bf{aesthetic\not101}}$