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3 years ago

11

Brian needs 10 quarts of Dr. Pepper. He can buy containers with 6 ounces of Dr. Pepper in them. How many containers does he need

to buy to have 10 quarts.

1 answer:

andrey2020 [161]3 years ago

5 0

Answer:

see below PLEASE GIVE BRAINLIEST

Step-by-step explanation:

1 quart = 32 ounces

10 x 32 = 320 ounces needed

320 ÷ 6 = 53.33

Since he can't buy half of a container he would need to purchase 54 containers.

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There is no x, therefore there is no slope.

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Answer:

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Step-by-step explanation:

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2 years ago

Meghan earns 20.00 dollars by walking dogs. She uses all of her earnings to buy a shirt for 12.85 dollars and some stickers for

PIT_PIT [208]

Answer:

She bought 11 stickers

Step-by-step explanation:

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3 years ago

Read 2 more answers

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

<u>ii. (4,2.5)</u>

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

<u>ill. (5,5)</u>

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

<u>iv. (3,2)</u>

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

Applying GCF and LCM to fraction Operations?<br>.<br>. PLZ HELP

I am Lyosha [343]

When multiplying fractions just multiply the numerator and denominators together, then simplify the fraction you get.

To solve the addition problem, first convert 2 and 1/2 to an improper fraction. It should be 5/2. Now 3/8 and 5/2 must be added together.

To add these, they must have the same denominator. Let's give 5/2 a denominator of 8, so it matches 3/8.

To give 5/2 a denominator of 8, you are starting with a denominator of 2. 2 × 4 = 8, so you must multiply 5/2 by 4.

You should get 20/8. Now you have to add 20/8 and 3/8. The only thing you add is the numerator, so you should get 23/8 as a final answer.

For the subtraction problem, do these same steps to make the fractions you must subtract have the same denominator, then subtract only the numerator to get the answer. Once you solve the subtraction problem, text me what you got so I can check it for you. :)

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3 years ago