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gizmo_the_mogwai [7]

1 year ago

7

Line I has a slope of 13/7. The line through which of the following pair

1 answer:

ivolga24 [154]1 year ago

3 0

Answer:

Step-by-step explanation:

You need to find the set of points that will yield a slope that is the negative reciprocal of the slope of Line L because perpendicular lines have negative reciprocal slopes. The negative reciprocal of 13/7 is -7/13. Which set of points will produce this result? The formula for finding the slope is:

m = (y2 - y1)/(x2 - x1)

Consider the second set of coordinates.

(2 - (-5))/(-7 - 6) = (2 + 5)/(-13) = -7/13

The second set of coordinates satisfy the condition.

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How do I find the slope if a line when y=4x+5

DaniilM [7]

Answer:

slope =4

Step-by-step explanation:

The slope intercept equation of a line is written in the form

y= mx+b

where m is the slope and b is the y intercept.

Since y =4x+5 is written is this form, we can see that 4 is the slope and 5 is the y intercept

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3 years ago

Solve for x, Correct to one decimal place where 0°<x<90° <br><br><br>Sin2x=0,291

Ksivusya [100]

Answer:

Step-by-step explanation:

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2 years ago

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gtnhenbr [62]

Answer:

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Step-by-step explanation:

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3 years ago

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dedylja [7]

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1/3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve for x write the exact answer using either base -10 or base-e logarithms

jeka57 [31]

<u>Given</u>:

The given expression is $2^{x+5}=13^{2 x}$

We need to determine the value of x using either base - 10 or base - e logarithms.

<u>Value of x:</u>

Let us determine the value of x using the base - e logarithms.

Applying the log rule that if $f(x)=g(x)$ then $\ln (f(x))=\ln (g(x))$

Thus, we get;

$\ln \left(2^{x+5}\right)=\ln \left(13^{2 x}\right)$

Applying the log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ , we get;

$(x+5) \ln (2)=2 x \ln (13)$

Expanding, we get;

$x \ln (2)+5 \ln (2)=2 x \ln (13)$

Subtracting both sides by $5 \ln (2)$ , we get;

$x \ln (2)=2 x \ln (13)-5 \ln (2)$

Subtracting both sides by $2 x \ln (13)$ , we get;

$x \ln (2)-2 x \ln (13)=-5 \ln (2)$

Taking out the common term x, we have;

$x( \ln (2)-2 \ln (13))=-5 \ln (2)$

$x=\frac{-5 \ln (2)}{\ln (2)-2 \ln (13)}$

$x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

Thus, the value of x is $x=\frac{5 \ln (2)}{2 \ln (13)-\ln (2)}$

6 0

3 years ago