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Vsevolod [243]
3 years ago
5

I don’t understand how to solve this graph. (Y=MX+B)

Mathematics
1 answer:
Alla [95]3 years ago
5 0

Answer:

The equation of line shown in the graph is \mathbf{y=-\frac{1}{2}x -1}

Step-by-step explanation:

We need to find equation of the line shown in graph.

The equation of line will be in slope-intercept form y=mx+b where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding y-intercept

Looking at the graph, we can find y-intercept when x =0, the value of y is known as y-intercept.

So, when x =0, y=-1

So, y-intercept is -1

Finding Slope

Now, for finding slope, consider 2 points on graph

(0,-1) and (-2,0)

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=0, y_1=-1, x_2=-2, y_2=0

Putting values and finding slope:

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{0-(-1)}{-2-0} \\Slope=\frac{0+1}{-2-0} \\Slope=\frac{1}{-2} \\Slope=-\frac{1}{2}

So, slope is m=-\frac{1}{2}

Equation of line

Now, equation of line having slope m=-\frac{1}{2} and y-intercept b = -1 is

y=mx+b\\y=-\frac{1}{2}x -1

So, equation of line shown in the graph is \mathbf{y=-\frac{1}{2}x -1}

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Solve 3x^2 + 6x+15=0
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Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Step-by-step explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So , from given eq , the value of x is now obtain as

x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, x =  \frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}

Or, x = \frac{\sqrt{-144} }{6}

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Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )  Answer

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Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

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Step-by-step explanation:

Hey there!

Please look your required answer in pictures.

<u>Hope</u><u> it</u><u> helps</u><u>!</u>

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