(x - 6) * 2
I'm assuming this is the expression that you typed out, if it isn't, please let me know in the comments :)
Use the distributive property:
= 2(x) - 2(6)
Multiply and simplify
= 2x - 12
This should be the expression that is equivalent to the original. Let me know if you need any clarifications, thanks!
Step-by-step explanation:
Triangle 1 can have 30°, 75° and 75° angles whereas Triangle 2 can have 30°, 30° and 120° angles.
Since they do not have all 3 congruent angles, they are not similar.
Answer:
14+6=n=20
Step-by-step explanation:n=20
A.
This is because in each circle the lines increase by one, so from the triangle (3 lines) to the rectangle (4 lines) it only makes sense to put a pentagon (5 lines)
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
