On a number line, A is at negative 7 and B is at 3. What is the coordinate of C, which is two fifths of the way from A to B?

Mathematics

1 answer:

svetoff [14.1K]3 years ago

6 0

well, 2/5 of the distance AB is simply their product, thus 2/5 of AB is just (2/5)AB.

$\bf \stackrel{A}{-7}\stackrel{\textit{7 units}}{\rule[0.35em]{17em}{0.25pt}}0\stackrel{\textit{3 units}}{\rule[0.35em]{10em}{0.25pt}}\stackrel{B}{3}
\\\\\\
AB=7+3\implies AB=10~\hspace{7em}\cfrac{2}{5}AB\implies \cfrac{2}{5}(10)\implies 4
\\\\\\
-7\rule[0.35em]{2em}{0.25pt}-6\rule[0.35em]{2em}{0.25pt}-5\rule[0.35em]{2em}{0.25pt}-4\rule[0.35em]{2em}{0.25pt}\boxed{-3}$

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