Your are designing a rectangular birthday card for a friend. You want the card's length to be 1 inch more than twice the card's width. The area of the card is 88 square inches. What is the width of the card to the nearest tenth of an inch?
1 answer:
The width of the card to the nearest tenth of an inch is 6.15 inches
<h3>Area of rectangle</h3>
Width = x Length = 2x + 1 Area = 88 square inches
Area of a rectangle = Length × Width
88 = (2x + 2) × x
88 = 2x² + 2x
2x² + 2x - 88 = 0
x = -b ± √b² - 4ac / 2a
= -2 ± √2² - 4(2)(-88) / 2(2)
= -2 ± √4 - (-704) / 4
= -2 ± √708 / 4
= -1/2 ± √177/2
x = 6.15 or -7.15 inches
The width of the rectangle can not be negative, so, 6.15 inches is the width.
Learn more about rectangle :
brainly.com/question/13048427
#SPJ1
You might be interested in
Answer:
Segment addition postulate
I would multiply both sides of the equation by 2 .
Work = force *distance
<span>D.The model predicts that for each additional degree that the high temperature is above 70°F, the total number of cones sold increases by 3.7.</span>
Answer:
(9,2)
Step-by-step explanation:
m (8,6)
(7,10)
find the coordinates of the unknown endpoint
(9,2)
