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MrMuchimi
2 years ago
9

Your are designing a rectangular birthday card for a friend. You want the card's length to be 1 inch more than twice the card's

width. The area of the card is 88 square inches. What is the width of the card to the nearest tenth of an inch?
Mathematics
1 answer:
klemol [59]2 years ago
5 0

The width of the card to the nearest tenth of an inch is 6.15 inches

<h3>Area of rectangle</h3>

  • Width = x
  • Length = 2x + 1
  • Area = 88 square inches

Area of a rectangle = Length × Width

88 = (2x + 2) × x

88 = 2x² + 2x

2x² + 2x - 88 = 0

x = -b ± √b² - 4ac / 2a

= -2 ± √2² - 4(2)(-88) / 2(2)

= -2 ± √4 - (-704) / 4

= -2 ± √708 / 4

= -1/2 ± √177/2

x = 6.15 or -7.15 inches

The width of the rectangle can not be negative, so, 6.15 inches is the width.

Learn more about rectangle:

brainly.com/question/13048427

#SPJ1

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