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Levart [38]
3 years ago
11

What is the work required to raise a 10. kg object from the surface of the earth to a height of 2.0 m?

Mathematics
1 answer:
Damm [24]3 years ago
5 0
Work = force *distance
W= weight *height
W= (10kg) (9.8 N/kg)(2m) = 198 Joules
Hope this helps!
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Mark can make 42 birdays cakes in 7 days how many birthday cakes can mark make in 5 days?
iragen [17]
42 cakes in 7 days, that's 42/7= 6 cakes per day
6*5=30
8 0
3 years ago
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What is the equation of the line shown below?
miskamm [114]

Answer:

y= 1x - 1

Step-by-step explanation:

Slope-intercept form: y=mx + b

(-4,-5) (5,4)

m= (y2 - y1)/(x2 - x1) = (4+5)/(5+4)=1

4=1(5)+b

4=5 + b    4-5=b    b= -1

y= 1x - 1

7 0
3 years ago
How to compare 2 5/9 and 21/3
max2010maxim [7]

Answer:

2 5/9 is less than 21/3;  2 5/9 < 21/3

Step-by-step explanation:

<u>Step 1:  Convert 2 5/9 into an improper fraction</u>

2 5/9 = 2 * 9/9 + 5/9 = 18/9 + 5/9 = 23/9

<u>Step 2:  Convert 21/3 so the denominator is 9</u>

21*3 / 3*3 = 63/9

<u>Step 3:  Compare</u>

<em>23/9 < 63/9</em>

<em />

Answer:  2 5/9 is less than 21/3;  2 5/9 < 21/3

5 0
3 years ago
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If the initial amount of iodine-131 is 537 grams , how much is left after 10 days?
viktelen [127]

Answer:

225.78 grams

Step-by-step explanation:

To solve this question, we would be using the formula

P(t) = Po × 2^t/n

Where P(t) = Remaining amount after r hours

Po = Initial amount

t = Time

In the question,

Where P(t) = Remaining amount after r hours = unknown

Po = Initial amount = 537

t = Time = 10 days

P(t) = 537 × 2^(10/)

P(t) = 225.78 grams

Therefore, the amount of iodine-131 left after 10 days = 225.78 grams

4 0
3 years ago
MATH HELP PLZZZZZ!!! 10pts
kykrilka [37]
First i got the area which is : A= a+b divided by 2 x height 
=2.5+3.5 divided by 2 x 2= 6
Area = 6

To get the perimeter you just add all the sides together so: 3.5+2.5+2.5+2.5= 11
8 0
3 years ago
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