Answer:
#5
Area = Area of bigger triangle - Area of small triangle
#8
Area = area of square + area of two right angled triangles
This is known as Einstein's proof, not because he was the first to come up with it, but because he came up with it as a 15 year old boy.
Here the problem is justification step 2. The written equation
BC ÷ DC = BC ÷ AC
is incorrect, and wouldn't get us our statement 2, which is correct.
For similar triangles we have to carefully pair the corresponding parts to get our ratios right:
ABC ~ BDC means AB:BD = BC:DC = AC:BC so BC/DC=AC/BC.
Justification 2 has the final division upside down.
Answer:
x = e^2/2 + 3
Step-by-step explanation:
Solve for x:
log(2 x - 6) = 2
Hint: | Eliminate the logarithm from the left hand side.
Cancel logarithms by taking exp of both sides:
2 x - 6 = e^2
Hint: | Isolate terms with x to the left hand side.
Add 6 to both sides:
2 x = e^2 + 6
Hint: | Solve for x.
Divide both sides by 2:
Answer: x = e^2/2 + 3
Answer: -4
Step-by-step explanation: -4/4 = -1
Please mark Brainliest!
Circumerence=2pir or dpi were r=radius and d=diameter
11pi=2pir
divid eobt sides by pi
11=2r
dvide 2
5.5=r
11pi=dpi
divide both sides by pi
11=d
diameter=11in
radius=5.5 in
