Answer:
Step-by-step explanation:
total is 240 then the bigger areas are 60* so S is 40*
Answer:
0.0035289
Step-by-step explanation:
From the question;
mean annual salary = $63,500
n = sample size = 31
Standard deviation = $6,200
Firstly, we calculate the z-score of $60,500
Mathematically;
z-score = x-mean/SD/√n = (60500-63500)/6200/√(31) = -2.6941
So we want to find the probability that P(z < -2.6941)
We can get this from the standard normal table
P( z < -2.6941) = 0.0035289
50 students participated in the survey, if you need help with 2, 3, & 4, just comment and ask
Answer:
-8,6
Step-by-step explanation:
from what i can tell this is a 1D problem. |E-G|=7, and E=-1, so -1-G=+-7. G=-8 or 6