Question

Given that the molar mass of CO₂ is 44.01 g/mol, how many liters of oxygen is required at STP to produce 88.0 g of

Answer 1

From the reaction, the volume of the oxygen required is 89.6 L.

What is stoichiometry?

The term stoichiometry has to do with the process by which the mass of reactants or products in a reaction is obtained from the  balanced reaction equation.

In this case, the balanced reaction is equation is;

CH₄  +  2 O₂    →    CO₂  +  2 H₂O

Number of moles of CO2 = 88.0 g/44 g/mol = 2 moles

2 moles of O2 produced 1 mole of CO2

x moles of O2 produces 2 moles of CO2

X = 4 moles

1 mole of oxygen occupies 22.4 L hence 4 moles of oxygen occupies 4 * 22.4 L = 89.6 L

Learn more about stoichiometry:brainly.com/question/1384613

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